If P is the incenter of JKL, find each measure

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Answer:

Its really simple look it up at some site

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Jesse has a storage container in the shape of a right rectangular prism. The volume of the container is 43.875 cubic meters, the

Gnom [1K]

Answer:

The height is 2.25 meters.

Step-by-step explanation:

The volume of a right rectangular prism is the product of the length, width, and height. So it would be V=w*l*h.

Because you have been given the values of the volume, width, and length, you can plug in those values into the equation to find the height. It should look like this: 43.875=5 * 3.9 * h

Then you can divide both sides of the equation by 5 * 3.9.

So... 43.875/(5*3.9)=h

therefore h= 2.25.

hope this explanation makes sense!

4 0

3 years ago

Read 2 more answers

For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$