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mr Goodwill [35]
2 years ago
6

5 ⟌94.3 108.86 18.86 188.6 18.68

Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

18.86

Step-by-step explanation:

5 ⟌94.3

90 ÷ 5 = 18

   18

5 ⟌94.3

    -90

-----------------

      4.3

cant divide by 4 so add a decimal

5 × 0.8 = 4

   18.8

5 ⟌4.3

   - 4.0

---------------

     0.3

5 × 0.06 = 0.3

  18.86

5 ⟌0.3

  - 0.3

--------------

     0

I hope this helps!

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Urgent help algebra 2
Rudiy27
Slope-intercept you have right:
y=3/4x-7

Point slope form is:
y − y1 = m(x − x1)

so

y +7 = 3/4(x -0)

or

y + 7 = 3/4x
6 0
1 year ago
1/6d + 2/3 = 1/4(d-2) how to solve
natita [175]
Greetings!

Solve for d.
1/6d + 2/3 = 1/4(d-2)
Distribute the Parenthesis.
1/6d + 2/3 = 1/4*d+1/4*-2
1/6d + 2/3 = 1/4d+1/4*-2/1
1/6d + 2/3 = 1/4d-2/4
Reduce.
1/6d + 2/3 = 1/4d-1/2
Add -2/3 to both sides.
(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)
Simplify.
1/6d=1/4d-3/6-4/6
1/6d=1/4d-7/6
Add -1/4d to both sides.
(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)
Simplify.
2/12d)-3/12d=-7/6
-1/12d=-7/6
Divide both sides by -1/12.
(-1/12d)/-1/12=(-7/6)/-1/12
Simplify.
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d=84/6
Reduce.
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Hope this helps.
-Benjamin
7 0
3 years ago
1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)
Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that \mu = 8, \sigma = 1.5

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 8}{1.5}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 6.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.5 - 8}{1.5}

Z = -1

Z = -1 has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

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