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2 years ago

5 ⟌94.3 108.86 18.86 188.6 18.68

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

4 0

Answer:

18.86

Step-by-step explanation:

5 ⟌94.3

90 ÷ 5 = 18

5 ⟌94.3

-90

-----------------

4.3

cant divide by 4 so add a decimal

5 × 0.8 = 4

18.8

5 ⟌4.3

- 4.0

---------------

0.3

5 × 0.06 = 0.3

18.86

5 ⟌0.3

- 0.3

--------------

I hope this helps!

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Urgent help algebra 2

Rudiy27

Slope-intercept you have right:
y=3/4x-7

Point slope form is:
y − y1 = m(x − x1)

so

y +7 = 3/4(x -0)

or

y + 7 = 3/4x

6 0

1 year ago

1/6d + 2/3 = 1/4(d-2) how to solve

natita [175]

Greetings!

Solve for d.
$1/6d + 2/3 = 1/4(d-2)$
Distribute the Parenthesis.
$1/6d + 2/3 = 1/4*d+1/4*-2$
$1/6d + 2/3 = 1/4d+1/4*-2/1$
$1/6d + 2/3 = 1/4d-2/4$
Reduce.
$1/6d + 2/3 = 1/4d-1/2$
Add -2/3 to both sides.
$(1/6d + 2/3)+(-2/3)=(1/4d-1/2)+(-2/3)$
Simplify.
$1/6d=1/4d-3/6-4/6$
$1/6d=1/4d-7/6$
Add -1/4d to both sides.
$(1/6d)+(-1/4d)=(1/4d-7/6)+(-1/4d)$
Simplify.
$2/12d)-3/12d=-7/6$
$-1/12d=-7/6$
Divide both sides by -1/12.
$(-1/12d)/-1/12=(-7/6)/-1/12$
Simplify.
$d=(-7/6)*-12/1$
$d=84/6$
Reduce.
$d=14/1$
$d=14$

Hope this helps.
-Benjamin

7 0

3 years ago

1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)

Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that $\mu = 8, \sigma = 1.5$