Answer:
x=9/2
Step-by-step explanation:
Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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The answer is 4.
The easiest way to determine the value of statements like this is to turn the percentage into a decimal and then multiply.
20% * 20
.20 * 20
4
This looks like the additive inverse property, because when you add something to its negative counterpart (or its additive inverse), you get 0 as a sum.
Another example would be 2+ (-2) = 0. -2 is the additive inverse for 2.
