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Marat540 [252]
3 years ago
14

Question1) Describe three scenarios that involve a real-world linear or exponential function. At least one must be exponential.

Identity whether your scenarios are linear or exponential. Provide an explanation to support your answers.. (Mark Brainliest.)​
Mathematics
1 answer:
elixir [45]3 years ago
5 0

Answer:

1) Let's suppose that you go in a straight line, in a car that moves at a constant speed of 80km/h.

Then the distance from your house (assuming that you start the drive in your house) can be modeled with a linear equation:

D(t) = 80km/h*t

where t is time in hours.

This will be a linear function.

2) Suppose that you have a population of some animal, that grows by 2% each month, and initially, there are 100 individuals of that animal.

Then the first month, the population is 100.

The second month the population increased by a 2%, then it will be:

100 + 100*0.02 = 100*(1.02)

The third month, the population will be 100*(1.02) + 0.2*100*(1.02) = 100*(1.02)^2.

and so on, this is an exponential relation, where the population as a function of the number of months, can be written as:

P(m) = 100*(1.02)^(m - 1)

3) Suppose that you have $100 saved, and each month you can save another $80, let's find a function that says the amount of money that you have saved as a function of the number of months. S(m)

The month number zero (before you started saving) you had $100 saved.

S(0) = $100.

One month after, you have saved $80 more, then you have:

S(1) = $100 + $80

Another month after, you have:

S(2) = $100 + $80 + $80 = $100 + 2*$80

And so on, you already can see the pattern, after m months, you will have:

S(m) = $100 + m*$80 saved.

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Find the L.C.M. of 16, 30 and 48​
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In the following table of values, the first differences are
ExtremeBDS [4]

Answer:

-7

Step-by-step explanation:

Given

\begin{array}{ccc}x & {y} & {First\ difference} & {-2} & {34} & {}&{-1} & {27} & {} &{0} & {20} & {} & {1} & {13} & {} & {2} & {6} &{} \ \end{array}

Required

The first difference

To do this, we simply calculate the difference between the consecutive y-values.

i.e.

d = y_{n+1} - y_n

So, we have:

d = y_2 - y_1 = 27 - 34 = -7

d = y_3 - y_2 = 20 - 27 = -7

d = y_4 - y_3 = 13 - 20 = -7

d = y_5 - y_4 = 6-13 = -7

<em>Hence, the first differences are -7 (all through)</em>

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3 years ago
I need much help plz
salantis [7]

Answer:

77

Step-by-step explanation:

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x + 9y

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5+9(8)

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