The cost of one ticket is $0.75
A conservative vector field
![\mathbf f](https://tex.z-dn.net/?f=%5Cmathbf%20f)
has curl
![\nabla\times\mathbf f=\mathbf0](https://tex.z-dn.net/?f=%5Cnabla%5Ctimes%5Cmathbf%20f%3D%5Cmathbf0)
. In this case,
![\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0](https://tex.z-dn.net/?f=%5Cnabla%5Ctimes%5Cmathbf%20f%3D12xy%5E2z%281-z%29%5C%2C%5Cmathbf%20j%2B4yz%5E2%282z-3x%29%5C%2C%5Cmathbf%20k%5Cneq%5Cmathbf%200)
so the vector field is not conservative.
Answer: The second graph
In all but the 3 graphs, the data is perfectly symmetrical. This means that the mean and the median would be the same.
However, in the second graph the data is skewed to the right. This means that the mean would also be skewed to the right due to the larger scores there. Using the median in this case would give a clearer picture of the data.
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.
c = 48b
96 = 48(2)
96 = 96.
Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
Answer:
are you just listing defnitions or what
Step-by-step explanation: