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-BARSIC- [3]
3 years ago
9

What does 6 - 6 + 3 =

Mathematics
2 answers:
shepuryov [24]3 years ago
5 0

Step-by-step explanation:

6 - 6 + 3

0 + 3

3

Mice21 [21]3 years ago
3 0

Answer:

3

Step-by-step explanation:

You might be interested in
Circumference of the circle
dimulka [17.4K]

Answer:

The formula of circumference in a circle is 3.14 times diameter.

Step-by-step explanation:

3.14×20=62.8

The circumference is 62.8

8 0
3 years ago
Point U has Coordinates (-5,1) and point V has coordinates (7,9) find the coordinates of the midpoint of UV
frutty [35]

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

= ( -6 , 5).

Midpoint of a Line Segment:

A line segment's midpoint is a point that divides the line segment across two equal sections. The midpoint of a line segment with coordinates at both ends X₁ , Y₁ and  X₂, Y₂ is calculated using:

<h3>According to the given data:</h3>

Point U has Coordinates (-5,1).

point V has coordinates (7,9).

Find  coordinates of the midpoint of UV = ?

We know that to find Midpoint of a Line Segment:

                               = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Where U

           X₁ = -5

           Y₁ = 1

Whare V

           X₂ = 7

           Y₂ = 9

Putting the value in the formula:

UV = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

       = (-5 + 7)/2 , (1 + 9)/2

       = -6 , 5

The mid point of the given  Coordinates U= (-5,1) and point V = (7,9):

= ( -6 , 5).

To know more about Midpoint of a Line Segment visit:

brainly.com/question/13792156

#SPJ9

4 0
1 year ago
Divya spends all of her free time playing with her building blocks. She owns building block sets with 333 pieces, 555 pieces, an
DiKsa [7]

Answer:

  5 sets

Step-by-step explanation:

The average number of pieces per set is the ratio of the total number of pieces to the total number of sets.

Let x represent the number of 3-piece sets. Then the total number of pieces is ...

  3x +5(5) +10(2) = 3x +45

The total number of sets is ...

  x +5 +2 = x +7

We want the ratio of these numbers to be 5 pieces per set:

  (3x +45)/(x +7) = 5

  3x +45 = 5x +35 . . . . . multiply by (x+7)

  10 = 2x . . . . . . . . . . subtract (3x+35)

  5 = x . . . . . . . . . divide by 2

Divya owns 5 sets with 3 pieces.

_____

<em>Alternate solution</em>

Each 10-piece set has 5 more pieces than average, so the two of them total 10 more pieces than average.

Each 3-piece set has 2 fewer pieces than average. The total number of 3-piece sets must have a total of 10 fewer pieces than average in order to balance the excess of the 10-piece sets. That is, there must be 10/2 = 5 of the 3-piece sets to have a total lof 10 fewer pieces than average.

Altogether, the differences from average must total zero.

5 0
3 years ago
Need help with number 2 ASAP! Try to show work! Thank you!!!
timofeeve [1]
C is the answer :) :)

4 0
3 years ago
Determine the t critical value for a lower or an upper confidence bound in each of the following situations. (Round your answers
Vinvika [58]

Answer:

A. 1.812

B. 1.753

C. 2.602

D. 3.747

E. 2.069

F. 2.453

Step-by-step explanation:

A. 95% confidence level, the level of significance = 5% or 0.05

Using t-table, the critical value for a lower or an upper confidence bound at 0.05 significance level with 10 degrees of freedom = 1.182

B. 95% confidence interval = 0.05 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.05 significance level with 15 degrees of freedom = 1.753

C. 99% confidence interval = 0.01 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 15 degrees of freedom = 2.602

D. 99% confidence interval = 0.01 level of significance; DF (n - 1) = 5- 1 = 4

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 4 degrees of freedom = 3.747

E. 98% confidence interval = 0.02 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.02 significance level with 23 degrees of freedom = 2.069

F. 99% confidence interval = 0.01 level of significance; df (n - 1) = 32 - 1 = 31

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 31 degrees of freedom = 2.453

7 0
4 years ago
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