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bekas [8.4K]
3 years ago
8

Which question is an example of a statistical question?

Mathematics
1 answer:
Hitman42 [59]3 years ago
4 0
I think the correct answer is c
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I have 2 questions, they're similar, but i have no idea. can someone please help me.
Dimas [21]

Answer:

First Picture:

\sqrt{x} -3=3-\sqrt{x}\\\\\x-3=0\\  +3  +3\\x=3

Second Picture:

2/3(9x-6)-4=9x-6

(6x-4-4=9x-6\\6x-8=9x-6\\   -9        -9\\\\-3x-8=-6\\      \\+8  +8\\-3x=2\\\\x=-2/3

5 0
3 years ago
Each of the 32 candidates can be assigned a unique sequence of outcomes of the 5 coin flips (e.g., HHHHH, HHHHT, etc). Use a sys
Bogdan [553]

Answer:

Step-by-step explanation:

Edmentum answer

8 0
3 years ago
Dilbert invests $10,000 at 2% simple interest for 1 year. How
FinnZ [79.3K]

Answer:

8.79299999999

Step-by-step explanation:

no se hablar inglés gracias

6 0
3 years ago
Pls help!I have trouble with this but ik everything is supposed to add up to 360 degrees
Ratling [72]

Because each of these angles are 90 degrees, we know they're each equal to each other.

Let's find the value of the variable y first.

We can use 5y - 17 = 2y + 50 to find the value of y.

5y - 17 = 2y + 50

-2y from both sides

3y - 17 = 50

+17 to both sides

3y = 67

Divide both sides by 3

y = 22.33

Now we need to find the value of x.

x + 44 = 7x - 248

-x from both sides

44 = 6x - 248

+248 to both sides

292 = 6x

Divide both sides by 6

x = 48.67


And there's your variables.

y = 22.33

x = 48.67

3 0
4 years ago
How do you do this!?!
Andrei [34K]

11x + y = 4

<u>x  |   y</u>

0  |   4

\frac{4}{11} |   0

<em>plot the y-intercept (0, 4) and the x-intercept (\frac{4}{11}, 0) </em>

or

11x + y = 4

<u>-11x      </u>  <u>-11x </u>

      y = -11x + 4      ⇒ m = \frac{-11}{1}, b = 4

<em>plot at point the y-intercept "b = 4" (0,4).  plot the next point using the slope "m = \frac{-11}{1}" from point (0,4), count down 11 and to the right 1 (1,-7).</em>

Using intercepts would not provide an accurate graph because you have to estimte where (\frac{4}{11}, 0) is, so it is best to use slope-intercept form.

***********************************************************************************************************

x + y = -2

<u>x  |   y</u>

0  |  -2

-2 |   0

<em>plot the y-intercept (0, -2) and the x-intercept (-2, 0)</em>

or

x + y = -2

<u>-x      </u>  <u> -x </u>

     y = -x - 2     ⇒ m = \frac{-1}{1}, b = -2

<em>plot at point the y-intercept "b = -2" (0,-2).  plot the next point using the slope "m = \frac{-1}{1}" from point (0,-2), count down 1 and to the right 1 (1,-3).</em>

Both methods are easy to use so either can be used.

**********************************************************************************************************

x - 2y = 18

<u>x  |   y</u>

0  |  -9

18 |   0

<em>plot the y-intercept (0, -9) and the x-intercept (18, 0)</em>

or

x - 2y = 18

<u>-x        </u>   <u> -x </u>

   -2y = -x + 18

    \frac{-2y}{-2} = \frac{-1}{-2}x + \frac{18}{-9}

       y = \frac{1}{2}x - 9

<em>plot at point the y-intercept "b = -9" (0,-9).  plot the next point using the slope "m = \frac{1}{2}" from point (0,-9), count up 1 and to the right 2 (2,-8).</em>

Using intercepts will make a large graph since you have to plot (18,0) so it is best to use the slope-intercept form.



6 0
3 years ago
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