Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
To solve this problem you must apply the formula for calculate the surface area of a circle, which is shown below:
SA=πir^2
where r is the radius of the circle
r=18 inches
By substituying values, you have that the surface area is:
SA=π(18 in)^2
SA=324π in^2
The answer is 324π in^2
Answer:
Step-by-step explanation:
|4r−12| = -(4r-12) when 4r-12< 0
4r< 12 so r<3
If sqrt x = 9 then x = 9*9 = 81
Answer is between 80 and 90.
