I need help finding the Answer to #1 and #2

Mathematics

1 answer:

kaheart [24]3 years ago

3 0

#3 is even I really hope this works

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1/3x + 1/3 = 7x + 5/ 2 find x

LekaFEV [45]

Answer:

-13/40 or -0.325

Step-by-step explanation:

6 0

2 years ago

Find the midpoint of a segment whose endpoints are (9, –7) and (–3, 5).

suter [353]

For this question, you would have to use the midpoint formula.
(X1 +X2 / 2 , Y1 + Y2 / 2)

In other words,
(9 + -3 / 2 , -7 +5 / 2)
(6 / 2 , -2 / 2)
(3 , -1)

Your midpoint is (3, -1)

7 0

3 years ago

Given f(x)=8x+13 and g(x)=x^2-5x, find (f-g)x

uysha [10]

(f-g)x= -x²+13x+13

Hope it helps you....

4 0

3 years ago

Helpp !! I Dont Understand This !

makvit [3.9K]

How to solve shaded regions on a trapezoid is simple.
First find the area of the whole trapezoid, or W but it already gives us that as 21.66 in squared.
Next, find the area of the non shaded region, or NS.
3.8*4.6=17.48 in
Lastly, subtract the NS from the W.
21.66 -17.48 =
NS= 17.48 in squared.
W= 21.66 in squared.
S= 4.18 in squared.

The answer is B- 4.18 in Squared

4 0

3 years ago

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
$=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2$

8 0

3 years ago