3 years ago

Help plz:)))I’ll mark u Brainliest

Mathematics

2 answers:

kiruha [24]3 years ago

7 0

Answer:

= 110 g AgCl

Step-by-step explanation:

NaCl + Ag(NO3) → AgCl + NaNO3

↓ ↑

mol → mol

NaCl AgCl

$\frac{45 g NaCl }{} \frac{1 mol NaCl}{57.44 g NaCl} \frac{1 mol AgCl}{1 mol NaCl } \frac{143.87 g AgCl}{1 mol AgCl} == 110 g AgCl$

Pavlova-9 [17]3 years ago

6 0

The correct
answer is 110.

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