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vodka [1.7K]
2 years ago
13

Evaluate sin(arcsin1.7)

Mathematics
1 answer:
Andrei [34K]2 years ago
7 0
Recall that \arcsin x is only defined for -1\le x\le1, and under this condition we have that \sin(\arcsin x)=x. But 1.7 > 1, so \arcsin1.7 is not a real number.
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