Answer:
Since the length of the drawing is 200 ft. and equivalent to 13.33 in. with a scale of 15 ft to 1 in. and the length of the paper is 11 in., Adoncia's drawing will not fit on the sheet of paper
Step-by-step explanation:
The given parameters are;
The scale of the drawing is 15 ft = 1 in.
The actual dimensions of the monument;
Height = 80 ft.
Length = 200 ft.
Therefore, we have;
The required dimension of the paper height = 80/15 = 16/3 = 5.33 in.
The required dimension of the paper length = 200/15 = 40/3 = 13.33 in.
The given paper dimension by 11 in. which is of a dimension of that of a standard letter paper size of 8.5 in. by 11 in.
Drawing length, 13.33 in. > Paper length > 11 in.
Adoncia's drawing will not fit on the sheet of paper.
A) Isolate y in both inequalities
1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3
B) Draw the lines for the following equalities:
1) y = 4 - x
2) y = 2x - 3
C) Shade the regions of solutions
1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3
The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3
I’m assuming you need to write an equation to display the relationship.
y=20x+50
Firstly, solve the effective annual interest (ieff) with the equation,
ieff = (1 + i/m)^m -1
where i is the interest rate and m is the number of times the interest is compounded in a year. In this problem, m is 12
Substituting the values,
ieff = (1 + 0.034/12)^12 - 1 =0.03453
To solve for the future (F) amount of the present investment (P),
F = P x (1 + ieff)^n
where n is number of years.
F = ($742) x (1 + 0.03453)^15
Thus, the answer is $1234.76.
