Please help me ! I don’t know !
2 answers:
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First plot the y-intercept.
The equation is in the form: y = mx + b where b is the y-intercept. So when x = 0, y = -5.
(0, -5)
Then choose any other x value to obtain the y value of that coordinate. For example, plug x = 2 in the equation.
y = -1/2x - 5
y = -1/2(2) - 5
y = -6
So a second point can be:
(2, -6)
Plotting these two points should make a linear graph as desired. I attached a picture of where the two points should be as reference.
The equation is in the form: y = mx + b where b is the y-intercept. So when x = 0, y = -5.
(0, -5)
Then choose any other x value to obtain the y value of that coordinate. For example, plug x = 2 in the equation.
y = -1/2x - 5
y = -1/2(2) - 5
y = -6
So a second point can be:
(2, -6)
Plotting these two points should make a linear graph as desired. I attached a picture of where the two points should be as reference.
Using the vertex of the equation, it is found that the correct option regarding the minimum number is given by:
C. n = 2(t - 2)² + 7.
<h3>What is the equation of a parabola given it’s vertex?</h3>The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient.
Considering a standard equation, given by:
y = ax² + bx + c.
The vertex is given by:
.
If a is positive, the vertex is a minimum value.
In this problem, the equation is given by:
n = 2t² - 8t + 15.
The coefficients are: a = 2, b = -8, c = 15.
Hence:
.
The minimum is 2 hours after 10 a.m., hence 12 p.m, and the function is:
C. n = 2(t - 2)² + 7.
More can be learned about the vertex of a quadratic equation at brainly.com/question/24737967
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