HELP!!!!!!!!!! WILL GIVE BRAINLY!!!!!!!

Mathematics

1 answer:

atroni [7]3 years ago

5 0

Answer:

141 $in^{2}$

Step-by-step explanation:

Area of a trapezium = $\frac{h}{2}$ (a + b)

h = height

a and b = upper and and lower lengths

Area of a trapezium = $\frac{9}{2}$ (10 + 16)

= $\frac{9}{2}$ × 26

= 117 $in^{2}$

Area of a triangle = $\frac{1}{2}$ × base × height

= $\frac{1}{2}$ × 6 × 8

= $\frac{1}{2}$ × 48

= 24 $in^{2}$

Total area = Sum of the areas of both the shapes

= 117 + 24

= 141 $in^{2}$

You might be interested in

Calculate the factorization 16w^2+48w+36=(4w+[1])^2

stiv31 [10]

Answer:

[1] = 6

x = -3/2 is the root

Step-by-step explanation:

A perfect square trinomial is of the form ...

(a + b)² = a² +2ab +b²

You have ...

a²=16w² ⇒ a = 4w
b² = 36 ⇒ b = 6
2ab = 2(4w)(6) = 48w

Then the factorization is ...

16w² +48w +36 = (4w +6)²

This will be zero when x = -6/4 = -3/2.

3 0

3 years ago

Transversal cuts parallel lines and at points X and Y respectively. The point nearest to C is X, and the point nearest to D is Y

hammer [34]

Answer: The answer is (B) ∠SYD.

Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.

We are given four angles, out of which one should be chosen which is congruent to ∠CXP.

The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.

For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.

Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.

Thus, we have

∠CXP ≅ ∠SYD.

So, option (B) is correct.