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valina [46]
3 years ago
14

An investment advisor believes that there is a 60% chance of making money by investing in a specific stock. If the stock makes m

oney, then there is a 50% chance that among those making money, they would also get a dividend. Find the probability that the investor makes money and receive a dividend.
Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

\mathbf{ 0.6 \times 0.5 = 0.3 }

Step-by-step explanation:

Let M denote the event that the stock makes money and D denote the event that the stock pays dividends.

It is given that P(M) = 0.6

Observe that the two events M and D are not independent because if the stock doesn't make money then it will not pay dividends. Therefore the event D | M^{c} (D given M does not occur) is a null event, i.e

P(D|M^{c}) = 0

It is also given that,

P(D|M) = 0.5

Recall that : P(D|M) = \frac{P(D \cap M)}{P(M)}

Here, we are required to find P(D \cap M)

P(D \cap M) =P(D|M) \times P(M)= 0.5 \times 0.6 = 0.3

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Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
I need help with some geometry work, there’s a pic x
avanturin [10]

Answer:

it is congruent by SAS axiom

So go with option A

Congruent -SAS

Hope it will help :)❤

3 0
3 years ago
13 cans of paint with 5/6 liters of paint in each were used to paint 4 identical cars. How can you calculate the amount of paint
brilliants [131]

Answer:

(B) 5/6 ·13÷4

(C) 5/6 ÷4·13

(D) 5/6 · 13/4

Step-by-step explanation:

Amount of paint per can = \[\frac{5}{6}\] liters.

Number of cans used to paint 4 cars = 13

Total amount of paint used for 4 cars = \[13 * \frac{5}{6}\] liters.

= \[\frac{13 * 5}{6}\] liters.

= \[\frac{65}{6}\] liters.

Total amount of paint used for 1 car = \[\frac{65}{6} \div 4\] liters.

= \[\frac{65}{24}\] liters.

Of the given options, option B,C and D correspond to the same value.

3 0
3 years ago
An angle has a measure of (5x + 7)º, and another angle has a measure of (2x + 54)°.
nadezda [96]

Answer:

17

Step-by-step explanation:

3 0
3 years ago
What is the answer to x-2=7
saul85 [17]

x-2=7

apply additon property of equality

x-2+2=7+2

x=9

6 0
3 years ago
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