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2 years ago

Can someone help please

Mathematics

1 answer:

Pepsi [2]2 years ago

6 0

Answer:

A: 5

B: 6

C: 3x^2 - 2x

D: 8

E: 22

Step-by-step explanation:

A: (-1)^2 + 4 = 5

B: (-4)^2 +4 = 16

2 x (-3) -4 = -10,

16-10=6

C: 3(x^2 + 4) = 3x^2 + 12

3x^2 + 12 -2x -4, simplify

3x^2 - 2x

D: g(3) = 2*3 -4 = 2

f(2) = 2^2 +4 = 8

E: f(3) = 3^2 + 4 = 13

g(13) = 2*13 - 4 = 22

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Which value of x makes the equation 2/3x-3=11 true?

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Answer:

x = 21

Step-by-step explanation:

To see for what value of x is the equation true, we have to solve x.

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Hope this helped!

<h3>~AH1807</h3><h3>Peace!</h3>

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2 years ago

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Answer:

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2 years ago

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tekilochka [14]

Answer:

x=Y/2−9/2

Step-by-step explanation:

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2 years ago

If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly

cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^n-x$ , where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

$P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%$

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

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2 years ago

There are 6 sixth graders , 7 seventh graders , and 8 eight graders entered in a contest.

fgiga [73]

Answer:

See below ~

Step-by-step explanation:

<u>P (6th grader)</u>

No. of 6th graders / Total students
6 / 6 + 7 + 8
6/21
2/7

<u>P (6th grader after)</u>

No. of 6th graders - 1 / Total students - 1
6 - 1 / 21 - 1
5/20
1/4

<u>Question 1 : P (Both 6th graders)</u>

P = P (6th grader) × P (6th grader after)
P = 2/7 x 1/4 = 2/28 = <u>1/14</u>

<u></u>

<u>Question 2 : P' (Both 6th graders)</u>

P' = 1 - P
P' = 1 - 1/14
P' = <u>13/14</u>

4 0

1 year ago

Read 2 more answers