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lana66690 [7]
3 years ago
15

The school baseball team has 3 pitchers. How many different 3-player pitching schedules can the coach choose from?

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

6 schedules

Step-by-step explanation:

First, decide if this situation describes a combination or a permutation by looking at the significance of order. Consider a specific example where the letters A – C represent the 3 different pitchers. The pitching order A, B, C is different from the pitching order B, C, A because the players will be pitching at different times. Therefore, this situation describes a permutation. Use the formula for finding the number of permutations when the number of pitchers is 3, so n = 3, and all 3 are taken at a time, so r = 3 as well.

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a car recently sold for $32,345. if there is a 6% sales tax on automobile sales, how much tax will be added to the price of the
geniusboy [140]
6% of $32,345 is $1,940.70, your decimal point is off by 1 place :)
7 0
2 years ago
For the given circle, find the value of x
Tpy6a [65]

Answer:

230

Step-by-step explanation:

the angle 115 is half of that arc

7 0
2 years ago
2
rusak2 [61]

Answer:

(1.13, 7.74) and (-4.13, 18.26)

Step-by-step explanation:

This can be solved in two ways:  mathematically and graphically.

<u>Graphing</u>

Plot both lines and find where they intersect.  See the attachment.

The intersection points are (1.13, 7.74) and (-4.13, 18.26)

<u>Mathematical</u>

y + 2x = 10

y = 10 - 2x

y = 3x² + 7x - 4

10 - 2x = 3x² + 7x - 4

3x² + 9x - 14 = 0

Solve this using the quadratic equation:

x = 1.13 and -4.13

Use these two values of x to find y:

y = 10 - 2x

y = 10 - 2(1.13)

y = 7.74

y = 10 -2x

y = 10 -2(-4.13)

y =  18.26

The two points are:

(1.13, 7.74) and (-4.13, 18.26)

7 0
2 years ago
What is 3/2=9/10k im having troble lots rly
tigry1 [53]

Answer:

k=  5 over 3  =1.667

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (3)/(2)-((9)/(10)*k)=0

simplify 9/10

 3      9

 — -  (—— • k)  = 0  

 2     10

simplify 3/2

 3    9k

 — -  ——  = 0  

 2    10

   Find the Least Common Multiple

     The left denominator is :       2  

     The right denominator is :       10

Least Common Multiple:

     10

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 1

Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      3 • 5

  ——————————————————  =   —————

        L.C.M              10  

  R. Mult. • R. Num.      9k

  ——————————————————  =   ——

        L.C.M             10

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3 • 5 - (9k)     15 - 9k

————————————  =  ———————

     10            10  

Pull out like factors :

  15 - 9k  =   -3 • (3k - 5)

-3 • (3k - 5)

 —————————————  = 0  

      10      

When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -3•(3k-5)

 ————————— • 10 = 0 • 10

    10    

Now, on the left hand side, the  10  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -3  •  (3k-5)  = 0

Solve :    -3   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    3k-5 = 0  

Add  5  to both sides of the equation :  

                     3k = 5

Divide both sides of the equation by 3:

                    k = 5/3 = 1.667

one solution was found

k = 5/3 = 1.667

hope it helps sry its so long

7 0
3 years ago
I need help with this one <br><br><br><br> Q13
horsena [70]

Answer:

x= 2 5/6

Step-by-step explanation:

1/3= 2/6

2 1/2= 2 3/6

2/6+ 2 3/6= 2 5/6

Hope this helps! :)

6 0
2 years ago
Read 2 more answers
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