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3 years ago

Write the quadratic equation in standard form: 2x^2+3x+7=x

Mathematics

1 answer:

Luden [163]3 years ago

5 0

2x²+3x+7=x

2x²+3x-x+7=0

2x²+2x+7=0

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Can someone explain to me how to do question number 6 please?

slavikrds [6]

Hope this helps but try to do process of elimination.

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3 years ago

Solve using elimination. 2x – 3y = -7 -8x + 3y = 19

Brums [2.3K]

Answer:

-2,1

Step-by-step explanation:

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3 years ago

Please answer asap!!

fredd [130]

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2 years ago

The concentration of dichlorodiphenyltrichloroethane (DDT - an infamous pesticide) in Lake Michigan has been declining exponenti

mojhsa [17]

Answer: A) $y=13e^{-0.1359t}$

B) H = 5.10

C) Yes

Step-by-step explanation: Exponential Decay function is a model that describes the reducing of an amount by a constant rate over time. Generally, it is written in the form: $y(t)=Ce^{rt}$

A) C is initial quantity, in this case, the initial concentration of DDT. To determine r, using the data given:

$y(t)=Ce^{rt}$

$2.22=13e^{13r}$

$e^{13r}=0.1708$

Using a natural logarithm property called power rule:

$13r=ln(0.1708)$

$r=\frac{ln(0.1708)}{13}$

$r=-0.1359$

The decay function for concentration of DDT through the years is $y(t)=13e^{-0.1359t}$

B) The value of H is calculated by $y=C(0.5)^{\frac{t}{H} }$

$2.22=13(0.5)^{\frac{13}{H} }$

$(0.5)^{\frac{13}{H} }=0.1708$

Again, using power rule for logarithm:

$\frac{13}{H} log(0.5)=log(0.1708)$

$\frac{13}{H} =\frac{log(0.1708)}{log(0.5)}$

$\frac{13}{H} =2.55$

H = 5.10

Constant H in the half-life formula is H=5.10

C) Using model $y(t)=13e^{-0.1359t}$ to determine concentration of DDT in 1995:

$y(24)=13e^{-0.1359.24}$

y(24) = 0.5

By 1995, the concentration of DDT is 0.5 ppm, so using this model is possible to reduce such amount and more of DDT.

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2 years ago

Use the graphs below to find the slope of each line (0,8),(8,1)

nignag [31]

Answer:

slope= -7/8

Step-by-step explanation:

y2-y1=1-8=-7

x2-x1=8-0=8

-7/8

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3 years ago