Several ways to prove but let's use one only
Here
- PQ is the radius of circle Q
Also
- PQ is the radius of circle P
Hence P and Q circles have same radius
Now
As both are radius of circle Q
And
As both are radius of circle P.
Hence as per transitive property
Now
Hence
∆PQR is equilateral
Use PEMDAS:-
3 - 3 × 6 + 2 = ?
3 - 18 + 2 = ?
-15 + 2 =
-13
3 - 3 × 6 + 2 = -13.
Answer:
64
Step-by-step explanation:
64
Hope it helped!
Well just substitute y (the first equation) into the second equation.
So
5x-4(5-3x)=-3
Then just solve the equation from there.
5x-20+12x=-3
17x=17
x=1
and if you need y, y=2
Answer:
a rhombus
Step-by-step explanation:
If you graph the problem, you can see the shape of the quadrilateral. I attached a picture of a graph below. I hope this helped you!! Have a great rest of your day.