Question

A current of 1.5A was passed through two electrolytes arranged

Answer 1

Answer:

0.59 g

Explanation:

The reaction at the first cathode;

Ag^+(aq) + e -----> Ag

if Q = It = 1.5 * 10 * 60 = 900C

According to Faraday's second law of electolysis; if we pass the same quantity of electricity through different electrolytes, the mass of substances deposited on each cathode is proportional to the equivalent weights.

Equivalent weight E = Atomic mass/valency

For Ag = 108/1 = 108

For Ni = 59/2 = 29.5

Hence

Let m1 = mass of Ag deposited =2.16

Let m2 = mass of Ni deposited

Let E1 = equivalent weight of Ag

Let E2 = equivalent weight of Ni

m1/m2 = E1/E2

2.16/m2 = 108/29.5

m2 = 2.16 * 29.5/108

m2 = 0.59 g