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d1i1m1o1n [39]
2 years ago
15

Explain how to use models to divide 2.1 by 0.7

Mathematics
1 answer:
tankabanditka [31]2 years ago
6 0

Answer:

The answer is 3

Step-by-step explanation:

0.7*3 = 2.1

Think of it this way

its basically 7 times what equals 21?

then you find out 7 timex 3 = 21

and then put the decimals

0.7 times 3 (0.7 + 0.7 + 0.7) = 2.1

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Game stop is having a 35% off sale on all their video games. if a game is originally $40.00, how much will it be during the sale
Nonamiya [84]
Discount = 35/100 * 40 = $14

Price = $40- $14 = $26
7 0
3 years ago
Write an equivalent expression to present patricia total earnings this week 7h + 135 + 5h = ?h + ?​
Paul [167]

Answer: 12 h + 135

Step-by-step explanation: 7h +135 + 5h = ?h + ?​

                                             7h +5h +135  

                                            =12h +135

So u combine like terms together  which are 7h and 5h which gives you 12 h.And then you have 135 left,so you add 12h to 135.

Ps.If you don't know what like terms are.I will explain down below.

Like terms are  variable that are the same.For an example 4y and 3y are like terms .Another example is 1/3 xy and 6xy .

Hope this helps :) and if it does please give brainliest .

8 0
2 years ago
Explain plz!!! Explain
ycow [4]

Answer: the answer is 8 rows


Step-by-step explanation: If there are 112 students and they need to be put in rows of 14 you must divide 112 by 14 to get the amount of rows.


7 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
Speed cell wireless offers a plan of $40 for the first 400 minutes, and an additional $0.50 for every minute over 400. Let t rep
Jlenok [28]

Answer:

Step-by-step explanation:

c(t)=40:0≤t≤400

=40+0.50 (t-400):t≥400

6 0
3 years ago
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