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Harman [31]
3 years ago
10

Analyze Maude's work. Is she correct? If not, what was

Mathematics
2 answers:
Ilya [14]3 years ago
6 0

Answer:

yes correct. hope helpful answer

strojnjashka [21]3 years ago
6 0

Answer:

C would be correct i got it right

Step-by-step explanation:

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Maristella is constructing an isosceles triangle to use as a model in her Algebra class. The perimeter of her triangle is 24 cm.
Vlada [557]

Isolating s, the equation written in terms of s is:

s = 12 - 0.5b

-------------------------

  • The equation for the length of the third side, as stated in the problem,("Maristella uses the equation b = 24 – 2s to find b, the length of the triangle's third side") is:

b = 24 - 2s

  • To solve for the lengths of the congruent sides, we isolate s, thus:

b = 24 - 2s

2s = 24 - b

Inverse of multiplication is division, thus:

s = \frac{24 - b}{2}

Separating into two fractions:

s = \frac{24}{2} - \frac{b}{2}

Solving each fraction:

s = 12 - 0.5b

A similar problem is given at brainly.com/question/5123313

3 0
3 years ago
Find the area of the shaded figure
nikitadnepr [17]

Answer:

forst find the area of the whole rectangle and then the area of the unshaded triangles then add the area of the two triangle and subtract it with the area of the rectange

Step-by-step explanation: area of rectangle is length × breadth and area of triangle is 1/2 × base × height

3 0
2 years ago
Help me plz I’m struggling with this
swat32

Answer:

if you zoom in a little bit and repost it i can help you

Step-by-step explanation:

5 0
3 years ago
Solve: 7/9 = x/3<br> 0.33<br> 2.33<br> 23.3<br> 33
Novosadov [1.4K]

Step-by-step explanation:

\frac{7}{9}  =  \frac{x}{3}  \\  \\ x =  \frac{7 \times 3}{9}  \\  \\ x =  \frac{7}{3}  \\  \\  \huge \red{ \boxed{x = 2. 33}}

4 0
3 years ago
Read 2 more answers
Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1
Shkiper50 [21]

Answer:

\displaystyle  -\frac{1}{2} \leq x < 1

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0

Simplifying by x-1 and taking x=1 out of the possible solutions:

\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

(6x^3+14x^2+10x+12)

is always positive and doesn't affect the result. It can be neglected. The expression

(x-\frac{1}{2})^2

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0

For the expression to be negative, both signs must be opposite, that is

(x+\frac{1}{2})\geq 0, (x-1)

Or

(x+\frac{1}{2})\leq 0, (x-1)>0

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

\displaystyle  -\frac{1}{2} \leq x < 1

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

\boxed{\displaystyle  -\frac{1}{2} \leq x < 1 }

7 0
3 years ago
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