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Harman [31]
2 years ago
10

Analyze Maude's work. Is she correct? If not, what was

Mathematics
2 answers:
Ilya [14]2 years ago
6 0

Answer:

yes correct. hope helpful answer

strojnjashka [21]2 years ago
6 0

Answer:

C would be correct i got it right

Step-by-step explanation:

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A group of band instructors answered a survey about hours of rehearsal per week and number of competitions won. The graph shows
IRISSAK [1]

Answer: B. 31

Step-by-step explanation:

This linear regression was constructed by relating the hours practiced per week and the number of competitions won.

Going by this graph, the number of competitions they can expect to win at 5 practices a week is 31.

This is derived by looking for the point where 5 competitions on the x-axis intersects with the line. This point is at 31 competitions on the y axis which would make it the answer.

5 0
2 years ago
Read 2 more answers
At the movie theatre, child admission is $6.30 and adult admission is $9.60 . On saturday, twice as many adult tickets as child
joja [24]

Let's assume

number of child tickets sold on saturday is x

number of adult tickets sold on saturday is y

On saturday, twice as many adult tickets as child tickets were sold

so, we get

y=2x

child admission is $6.30 and adult admission is $9.60

a total sales of $535.50

we get

6.30x+9.60y=535.50

now, we can plug y=2x

6.30x+9.60*2x=535.50

now, we can solve for x

25.5x=535.5

x=21

now, we can find y

y=2*21

y=42

so,

number of child tickets sold on saturday is 21

number of adult tickets sold on saturday is 42.........Answer


4 0
3 years ago
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
2 years ago
Help please I'm stuck
ZanzabumX [31]
Look at the solution ( again me)

7 0
3 years ago
The table shows the number of degrees the temperature increased or decreased over four days. On which day did the temperature ch
Luba_88 [7]
The correct answer is Friday
6 0
2 years ago
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