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gtnhenbr [62]
3 years ago
5

The nth term of a sequence is n²+1. What is the 9th term?

Mathematics
1 answer:
Dimas [21]3 years ago
5 0
Replacing 9 for the nth term of the sequence we get 9^2 + 1 = 82, Therefore the 9th term is = 82
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Al, Tom and Joe share €3000.
agasfer [191]

Answer:

Tom's share = €800

Step-by-step explanation:

Given that:

Amount shared by Al, Tom and Joe = €3000

Ratio of Al's share to Tom's share = 5 : 4

Joe's share = 1.5(Tom's share) = 1.5(4) = 6

Therefore,

Ratio of Al, Tom and Joe = 5 : 4 : 6

Let,

x be the number of times of amount each get.

5x + 4x + 6x = 3000

15x = 3000

Dividing both sides by 15

\frac{15x}{15}=\frac{3000}{15}\\x=200

Tom's share = 4x = 4(200) = €800

Hence,

Tom's share = €800

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3 years ago
Explain the step in subtracting the polynomials below. <br><br> (7x3− x − 5) − (3x3+ 5x -1).
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Answer:

It subtracts

Step-by-step explanation:

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Put these numbers in smallest to largest
xenn [34]

3.07, 3.7, 3.77, 7.3, 7.33

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2 years ago
Read 2 more answers
3x^3-8y^2 pls someone help
Natalija [7]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​
serg [7]

Answer:

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Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}

Multiply the numerators :

\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}

Multiply the denominators :

\frac{-18x^6y^4z^3}{36x^4y^2z^3}

Apply the negative rule :

-\frac{18x^6y^4z^3}{36x^4y^2z^3}

Cancel the common factor which is 18 :

-\frac{x^6y^4z^3}{2x^4y^2z^3}

Apply the addition exponent rule :

\frac{y^4z^3x^{6-4} }{2y^2z^3}

Subtract :

\frac{x^2y^4z^3 }{2y^2z^3}

Apply the rule for y :

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Subtract :

\frac{x^2y^2z^3 }{2z^3}

Cancel the common factor of z^3 :

-\frac{x^2y^2}{2}

5 0
3 years ago
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