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Whitepunk [10]
3 years ago
13

PROVE THAT TWO TRIANGLES ARE CONGRUENT USING THE SAS CONGRUENCE CRITERIA PLEASEEEEE I NEED ASAP DUE IN 15 MINS PLEEEEASE​

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

Side-Angle-Side is a rule used to prove whether a given set of triangles are congruent. If two sides and the included angle of one triangle are equal to two sides and included angle of another triangle, then the triangles are congruent.

Step-by-step explanation:

zimovet [89]3 years ago
6 0

Answer:

Step-by-step explanation:

The length of DE is congruent to the length of FG, which is sqrt(5). The length of EF and GH are congruent too. Two pairs of sides are congruent, one pair of angles are congruent (vertical), SAS

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Ms santos seashells into 4 row she puts 6 seashells in each row how many seachells are there altogether
kati45 [8]
4 rows and 6 seashells in each row. 
Row 1: 0 0 0 0 0 0
Row 2: 0 0 0 0 0 0
Row 3: 0 0 0 0 0 0
Row 4: 0 0 0 0 0 0

You add all of them together 6+6+6+6=24 
Or you could do 6x4 and your answer would be 24
So the answer to the question is 24 seashells. 
3 0
3 years ago
Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans
tatyana61 [14]

Answer:

  3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

  \dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}

__

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

  \dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}

__

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0
3 years ago
What’s the answer for y= (x-2)^2 +2 {x&lt;4.5}
stealth61 [152]

Answer:

x<4.5

Step-by-step explanation:

y =(x-2)^2 +2 {x<4.5}

add the power and then divide by 2 you get 4.5

8 0
3 years ago
The square shown has a perimeter of 32 units. The square is rotated about line k. What shape is created by the rotation and what
harkovskaia [24]
The perimeter of the square is calculated through the equation,
                                        4x = P
where P is the perimeter and x is the measure of the sides.

When P is 32 units then,
                                         32 units = 4(x)
                                                 x = 8 inches

This 8 inches is the diameter of the cylinder formed by the rotation. 
The circumference of the base is calculated through,
                            C = 2πr = πD
Substituting the known values,
                              C = π(8 units) = <em>8π units
</em>
<em></em>When π is equal to 3.14, we solve for the numerical value of the cylinder as follows,
<em>                                      C = 8(3.14) = 25.12 units
</em>
<em></em>Thus, the figure formed is a cylinder with base circumference equal to 25 units. The answer is the third choice. <em>
</em>
6 0
4 years ago
Read 2 more answers
Solve the formula v+f−e=2 for e
Bess [88]
Add e to both sides and subtract 2 from both sides :: v+f-2=e
8 0
3 years ago
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