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3 years ago

13

PROVE THAT TWO TRIANGLES ARE CONGRUENT USING THE SAS CONGRUENCE CRITERIA PLEASEEEEE I NEED ASAP DUE IN 15 MINS PLEEEEASE

2 answers:

Klio2033 [76]3 years ago

8 0

Answer:

Side-Angle-Side is a rule used to prove whether a given set of triangles are congruent. If two sides and the included angle of one triangle are equal to two sides and included angle of another triangle, then the triangles are congruent.

Step-by-step explanation:

zimovet [89]3 years ago

6 0

Answer:

Step-by-step explanation:

The length of DE is congruent to the length of FG, which is sqrt(5). The length of EF and GH are congruent too. Two pairs of sides are congruent, one pair of angles are congruent (vertical), SAS

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I need answer Immediately pls!!!!!!

Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

$n(U)=27$

$n(A)=7$

$n(B)=18$

$n(A'\cap B')=7$

We know that,

$n(A\cup B)=n(U)-n(A'\cap B')$

$n(A\cup B)=27-7$

$n(A\cup B)=20$

Now,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=7+18-n(A\cap B)$

$n(A\cap B)=7+18-20$

$n(A\cap B)=25-20$

$n(A\cap B)=5$

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

$\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}$

$\text{Probability}=\dfrac{5}{27}$

Therefore, the required probability is $\dfrac{5}{27}$ .

3 0

3 years ago

PLEASE HELP QUICK!!!

GrogVix [38]

The answer is 50pi.

8 0

3 years ago

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Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.

inysia [295]

It would be B! :) have a good day

3 0

3 years ago

Find the surface area of the cylinder (please help)

Misha Larkins [42]

Answer:

surface area we can also take it as total surface area

9 is the radius and 5cm is the height . as they asked total surface area we have to take the area of base so tht we can make it as

total surface area = csa of cylinder + area of base

we know that,

2pirh+pir²

pir(2h+r)

pir(2×5+9)

pir(10+9)

pir(19)

22/7×9×19

3762/7

=> 537.42 cm² is the answer.

4 0

2 years ago

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The graph shows the function of f(x)=(3.5)^x

GrogVix [38]

The one that passes through the origin. That one in the lower left part.

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3 years ago

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