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3 years ago

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You are going to draw 4 cards from a standard deck of 52 cards. How many different combinations of cards could you draw?

2 answers:

zloy xaker [14]3 years ago

5 0

Answer:

Step-by-step explanation:

To start with we can consider how many possibilities there are for the first card which is obviously 52, as any one of the cards in the deck can be found on the top of the pile. The next card is a bit trickier as there are only 51 possible cards that it could be as the first card takes up a spot. The third card now only has 50 possible cards it could and this continues all the way down to the last card.

is that good

Firlakuza [10]3 years ago

5 0

You can make 208 different combinations

Explanation: To find the combinations you can multiply 52 and 4 and you should get 208

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Consider multiplying 26.2 by 16.43 what would a mathematician say the answer is

IgorC [24]

In mathematics multiplying decimals is just like multiplying a whole number and ignoring the decimals., then just put the decimals in the answer – it is how many decimals does the two numbers combined.

First step:

Line the numbers on the right and do not a line the decimal points

26.2

× 16.43

Second Step:

Multiply the numbers starting on the right, just like multiplying a whole number and ignore the decimals.

26.2

<span> × 16.43</span>

786

1048

1572

<span>+ 262 </span>

430466

Third step: add the products

26.2

<span> × 16.43</span>

786

1048

1572

<span>+ 262 </span>

430.466 is the mathematician’s answer.

8 0

3 years ago

Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit

Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is $2$

Part 2) The vertex is the point $(1,8)$

Part 3) The equation of the axis of symmetry is $x=1$

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is $y=2x^{2}-4x+10$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

$x=h$

In this problem we have

$y=2(x-1)^{2}+8$ -----> this is the equation in vertex form of a vertical parabola

The value of $a=2$

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point $(1,8)$

so

$(h,k)=(1,8)$

The equation of the axis of symmetry is $x=1$

The equation of a vertical parabola in standard form is equal to

$y=ax^{2}+bx+c$

Convert vertex form in standard form

$y=2(x-1)^{2}+8$

$y=2(x^{2}-2x+1)+8$

$y=2x^{2}-4x+2+8$

$y=2x^{2}-4x+10$

see the attached figure to better understand the problem

7 0

3 years ago

All 6 members of the Valastro family have decided to

atroni [7]

Answer:

5

Step-by-step explanation:

7 0

3 years ago

Which expression is a difference of squares with a factor of 2x + 5? 4x2 + 10 4x2 – 10 4x2 + 25 4x2 – 25

Shtirlitz [24]

Answer:

4x^2 -25

Step-by-step explanation:

The other factor of the difference of squares is the "conjugate" of the given one: (2x -5). Then their product is ...

(2x +5)(2x -5) = (2x)^2 -(5)^2 = 4x^2 -25

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B7%7D-%5Csqrt%7B6%7D%20%7D%20%2B%5Csqrt%7B7%7D%20-%5Csqrt%7B6%7D" id

Radda [10]

Step-by-step explanation:

mark me brainlist.......

5 0

3 years ago