The result of rolling a number cube 7 times is a 7-digit number composed of digits 1,2,3,4,5 and 6 so that digits can repeat. The total number of possibilities is 6^7.
The number of possibilities where 4 appears exactly two times is 5^5*(7!-6!/2).
5^5 is the number of 5-digits numbers composed of digits 1,2,3,5 and 6 so that digits can repeat.
7! is the number of permutations of digits 1,2,3,4,4,5 and 6.
6! is the number of permutations of digits 1,2,3,{4,4},5 and 6.
We don't want to subtract all numbers where digits 4 appear side by side. That's why we must divide 6! by 2.
Finally, the probability is P=5^5(7!-6!/2)/7^7
Answer:
g(x) = |x-3| -4
Step-by-step explanation:
to shift right by 3, subtract three from x inside the absolute value.
to shift down by 4, subtract 4 outside of the absolute value.
g(x) = |x-3| -4
Answer:
Step-by-step explanation:
(47+1)/(3-6) = 48/-3 = -16
y + 1 = -16(x - 6)
y + 1 = -16x + 96
y = -16x + 95
Answer:
C.) i belive this is the correct one
Step-by-step explanation:
