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vlabodo [156]
3 years ago
6

Express 60 km/h in metres per second.

Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

16.667 metres per second

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A cone-shaped paper drinking cup is to be made to hold 33 cm3 of water. find the height and radius of the cup that will use the
alekssr [168]
The height and radius that will give us the smallest amount of paper, should have should have the perfect dimension, in that the diameter should be equal to the height. thus let the diameter be x, the height will be x and the radius will be x/2
thus the volume of the cone will be:
V=1/3πr^2h
=1/3*π*(x/2)^2*x
=0.262x^3
hence the value of x will be:
33=0.262x^3
x^3=125.95
x=(125.95)^(1/3)
x=5.0126=5.01 cm
thus the diameter=height=5.01cm
6 0
3 years ago
What are the steps to solving this? 70-8x=56+x
guapka [62]

Answer:

x = 14/9

Step-by-step explanation:

70 - 8x = 56 + x

- 8x - x = 56 - 70

- 9x = - 14

- x = - 14/9

x = 14/9

7 0
4 years ago
Read 2 more answers
An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the
julia-pushkina [17]

Answer:

The rate of decrease is: 43.2mm^3/min

Step-by-step explanation:

Given

l = 18mm

\frac{dl}{dt} = -0.8mm/min ---- We used minus because the rate is decreasing

Required

Rate of decrease when: l = 18mm

The volume of the cube is:

V = l^3

Differentiate

\frac{dV}{dl} = 3l^2

Make dV the subject

dV = 3l^2 \cdot dl

Divide both sides by dt

\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}

Given that: l = 18mm and \frac{dl}{dt} = -0.8mm/min

\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)

\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min

\frac{dV}{dt} = -43.2mm^3/min

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0
3 years ago
What are the x intercepts of the quadratic function? Y=-x^2+2x-1
saw5 [17]

Answer:

x = 1

Step-by-step explanation:

Given in the question the equation

y = -x² + 2x - 1

To find the x-intercept, substitute in 0 for y

0 = -x² + 2x - 1

To find value of x use quadratic equation

x = -b ± √b²-4ac / 2a

  here a = -1

           b = 2

           c = -1

x1 = -2 + √2²-4(-1)(-1) / 2(-1)

   = -2 + 0 / -2

   = -2 / -2

   = 1

x2 = -2 - √2²-4(-1)(-1) / 2(-1)

   = -2 - 0 / -2

   = -2 / -2

   = 1

8 0
4 years ago
At a point on the ground 35 ft from the base of a tree, the distance to the top of the tree is 1 ft more than 3 times the height
jolli1 [7]

Answer:

Step-by-step explanation:

This is a question that uses the Pythagorean Theorem.

a = 35 feet

b = x            which is the height of the tree.

c = 3*x + 1   so we are trying to find x.  Substitute into a b and c

a^2 + b^2 = c^2

35^2 + x^2 = (3x + 1)^2        

35^2 + x^2 = 9x^2 + 6x + 1     Subtract x^2 from both sides.

35^2 = 8x^2 + 6x + 1               Subtract 35^2 from both sides.

0 = 8x^2 + 6x + 1 - 35^2

0 = 8x^2 + 6x - 1224

Does this factor?

(x + 12.75)(x - 12)

x - 12 = 0 is the only value that works.

x = 12

The tree is 12 feet high.

Note: I used the quadratic formula to solve this.

6 0
4 years ago
Read 2 more answers
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