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babymother [125]
1 year ago
15

A collection of stamps consists of 3c stamps 5c stamps and 7c stamps. There are 6 more 3c stamps than 5c stamps and two more 7c

stamps than 3c stamps. The total value of the stamps is $1.94. How many 3c stamps are in the collection?
Mathematics
1 answer:
Deffense [45]1 year ago
6 0

The number of 3¢ stamps that are in the collection is: 22.

<h3>What is an expression?</h3>

An expression can be defined as a mathematical equation which is used to show the relationship existing between two or more variables and numerical quantities.

In this exercise, you're required to determine the number of 3 cents (3¢) . Therefore, we would translate the word problem into an algebraic expression and then evaluate it as follows:

<u>Note:</u> 100 cents (¢) is equal to 1 dollar ($).

A collection of stamps consists of 3¢ stamps, 5¢ stamps and 7¢ stamps; 3¢ + 5¢ + 7¢ = 194

6 more 3¢ stamps than 5¢ stamps; 3¢ = 5¢ + 6  ⇒ 5¢ = 3¢ - 6

Two more 7¢ stamps than 3¢ stamps; 7¢ = 3¢ + 2

Combining the above equations, we have:

3¢ + 3¢ - 6 + 3¢ + 2 = 194

9¢ = 198

¢ = 198/9

¢ = 22.

Read more on expressions here: brainly.com/question/17361494

#SPJ1

<u>Complete Question:</u>

A collection of stamps consists of 3¢ stamps 5¢ stamps and 7¢ stamps. There are 6 more 3¢ stamps than 5¢ stamps and two more 7¢ stamps than 3¢ stamps. The total value of the stamps is $1.94. How many 3¢ stamps are in the collection?

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user100 [1]

Answer:

128 feet squared

Step-by-step explanation:

you multiply 4 by 4 to get 16 ,

then you multiply 7 by 4 and get 28,

also multiply 28 by 4 and get 112 ,

finally add 112 and 16 to get 128


6 0
3 years ago
Choose the correct option.Immersive Reader (1 Point) (A) z-5=2 is an equation and z=5 is the solution of this equation (B) t+2&g
melomori [17]

Answer:

<h3>Find the explanation below</h3>

Step-by-step explanation:

A) Given the equation z - 5 = 2

To get the solution, we will add 5 to both sides and find z as shown;

z - 5 = 2

z - 5 + 5 = 2 + 5

z + 0 = 2+5

z = 7

Hence z = 5 is not the solution of the equation but z = 7

B) Given the inequality expression t+2>5

Substract 2 from both sides of the equation;

t+2 - 2>5 - 2

t + 0> 3

t>3

Hence the solution t = 4 is not true for the expression. The solution is t > 3

C) Given the expression  x-2=2, to get the solution to the expression, you will add 2 to both sides of the equation;

x - 2+ 2 = 2 + 2

x + 0 = 4

x = 4

Therefore x = 4 is the solution of this equation.

Based on the question, only Option C is correct

8 0
3 years ago
Umm plz help with just the first part
harkovskaia [24]

Answer:

Factored form: -2(x + 7) = 8, x = -11 (brainliest)?

Step-by-step explanation:

-2(x + 7) = 8

x + 7 = 8 / -2

x + 7 = -4

x = -4 - 7

= -11

6 0
4 years ago
5,000/7,000,000,000 simplified
riadik2000 [5.3K]
0.000000714 is the decimal version, but as a fraction its 5/7,000,000
3 0
3 years ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
4 years ago
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