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3 years ago

I NEED HELP ASAP PLEASE!!!

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

Answer:

Q2: -17

Q3: a) -5/2 b) g = -13

Step-by-step explanation:

2w+7 = -9

2w = -9 - 7

w = -16/2

w = -8

---

15 - 4w

= 15 - 4(-8)

= 15 - 32

= -17

----------------------

Q3:

a) 3/4(16m-24) = -48

16m -24 = -48 ÷ 3/4

16m = -64 + 24

16m = -40

m = -5/2

b) -20 = 1/6(36+12g)

-20 = 1/6 × 6(6+2g)

(cross out the 6 from 1/6 and 6)

-20 = 6 + 2g

-20-2g= 6

-2g = 6+20

-2g = 26

g = 26/-2

g = -13

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3 years ago

Consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number,

Aleksandr-060686 [28]

Answer:

The expected value of the points earned on a single roll in this game is $\dfrac{1}{6} = 0.1667$ .

Step-by-step explanation:

We are given that consider a game in which players roll a number cube to determine the number of points earned. If a player rolls a prime number, that many points will be added to the player’s total. Any other roll will be deducted from the player’s total.

Assuming that the numbered cube is a dice with numbers (1, 2, 3, 4, 5, and 6).

Here, the prime numbers are = 1, 2, 3 and 5

Numbers which are not prime = 4 and 6

This means that if the dice got the number 1, 2, 3 or 5, then that many points will be added to the player’s total and if the dice got the number 4 or 6, then that many points will get deducted from the player’s total.

Here, we have to make a probability distribution to find the expected value of the points earned on a single roll in this game.

Note that the probability of getting any of the specific number on the dice is $\dfrac{1}{6}$ .

Numbers on the dice (X) P(X)

+1 $\frac{1}{6}$

+2 $\frac{1}{6}$

+3 $\frac{1}{6}$

-4 $\frac{1}{6}$

+5 $\frac{1}{6}$

-6 $\frac{1}{6}$

Here (+) sign represent the addition in the player's total and (-) sign represents the deduction in the player's total.

Now, the expected value of X, E(X) = $\sum X \times P(X)$

= $(+1) \times \frac{1}{6} +(+2) \times \frac{1}{6} +(+3) \times \frac{1}{6} +(-4) \times \frac{1}{6} +(+5) \times \frac{1}{6} +(-6) \times \frac{1}{6}$