32.5 % of lab are wireless devices
<em><u>Solution:</u></em>
Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices
Now we can first find out total number of computers and devices in lab
total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices
total number of computers and devices in lab = 30 - 3 + 13 = 40
So there are 40 computers and wireless devices in lab
<em><u>To find: what percent of the lab are wireless devices</u></em>
So we have to find what percent of 40 is 13
Let "a" be the required percent
a % of 40 = 13

32.5 % of of lab are wireless devices
Answer:
Step-by-step explanation:
Part A:
The interquartile range is approximately 10
Part B:
The difference between the median values for each data set is approximately 6
Part C:
i) More widely distributed and concentrated to the beginning of the month
The better measure of the center for the male dataset is the median
ii) The skewed distribution
The mean is the better measure of center for the dataset
Part D;
A possible reason for the outlier is by chance
Answer:
46
ayo how r u doin siahsvsgshsgsgsgsg
50% is greater than 33 1/3% so overall it would be greater than the original
I thinks it’s C I maybe be wrong but it’s at least an answer