2(2d+4)=-3(d+2)
4d+8=-3d-6
4d+3d=-6-8
7d=-14
d=-14/7
d=-2
Step-by-step explanation:
f ( - 4) = 3 ( - 4) ² - 2( - 4)
=. 3 ( 16) + 8
=. 48 + 8 = 56
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The angle ∠EJS is bisected by the diagonal JS to form an angle of 62°
Response:
<h3>What properties of a rhombus can be used to find ∠EJS = 62?</h3>
Properties of a rhombus:
The lengths of the sides of a rhombus are equal
The measure of the opposite angles of a rhombus are equal
The diagonals bisect the interior angles of a rhombus
Given that JOSE is a rhombus, and ∠ESO = 124°, we have;
∠EJO = ∠ESO = 124° opposite angles of a rhombus
∠EJS = ∠OJS definition of bisected angle ∠EJO
∠EJS + ∠OJS = ∠EJO by angle addition
- ∠EJS + ∠OJS = 2×∠EJS = ∠EJO = 124°

Learn more about a rhombus here:
brainly.com/question/10689502