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fgiga [73]
3 years ago
15

The population of a parish is growing with an annual percentage rate compounded continuously. The population reaches 1.1 times i

ts previous size in 2 years. Find the annual percentage rate according to the exponential growth function
Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

Answer:

Growth rate = ln(1.1)/2

Step-by-step explanation:

Given:

P1 = 1.1 P0

Number of year n = 2

Computation:

P1 = P0[eⁿˣ]

x = growth rate

So,

1.1 P0 = P0[eⁿˣ]

1.1 = eⁿˣ

1.1 = e²ˣ

By taking log

Growth rate = ln(1.1)/2

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Thirty students in the fifth grade class listed their hair and eye colors in the table below: Brown hair Blonde hair Total Green
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Answer:

No, the events "brown hair" and "brown eyes" are not  independent.

Step-by-step explanation:

The table that represents the  hair and eye colors of thirty students of the fifth grade are given in table as:

                         Brown hair          Blonde hair              Total

Green eyes           9                       6                               15

Brown eyes          10                       5                              15

Total                     19                        11                             30

No, the events  "brown hair" and "brown eyes" are not independent.

Since, two events A and B are said to be independent if:

P(A∩B)=P(A)×P(B)

where P denotes the probability of an event.

Here we have:

A= students having brown hair.

B= students having brown eyes.

A∩B= students having both brown hair and brown eyes.

Now,

P(A)=19/30  (ratio of addition of first column to the total entries)

P(B)=15/30  ( ratio of addition of second row to the total entries)

Also,

P(A∩B)=10/30

Now as:

P(A∩B) ≠ P(A)×P(B)

Hence, the two events are not independent.

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