Answer:
6.32g
Explanation:
The mass of 1 mol of K is 40g, and the reaction needs 2 moles of K to produce 2 moles of KCl, so it needs 80g of K to produces 151g of KCl.
So you make a rule of three:
x = 3.35•151/80
x = 6.32g
To answer this, we look at the polarities of these molecules given. A molecule is said to be polar when there is an unequal shraing of electrons the opposite is called nonpolar.
CH4 = nonpolar
CH3OH = polar
CH3 CH3 = nonpolar
CH3 CH2 CH2 OH = polar
<span>CH3 CH2 CH2 CH2 CH2 CH3 = nonpolar</span>
<h2><u>Answer:</u></h2>
Component having Smallest Atomic Size is 'Helium' having range approx. 31pm
I have seen that numerous individuals are noting with respect to hydrogen Atom however the genuine reason is along a period (left to right) the nuclear number increments while the valence electrons stay in a similar shell. Along these lines because of the expanding atomic charge (pulling electrons closer to the core) the radii of the iotas decline left to right.
Furthermore, as should be obvious from the table, Hydrogen and Helium are in a similar period so Helium having littlest size
Answer: An indicator is itself a weak acid or weak base but a special one. The colour of the acid form is different from the colour of the base form. So you can tell when the pH of your solution has changed from being one to the other by seeing the colour change from one to the other. The particular pH where that colour change occurs depends on the particular indicator you use. The most common indicator in UG Chem Labs is probably the one called Phenolphthalein when it has its proton attached, it is colourless like water but when the proton comes off it is pink. This change happens around pH=8–9. any solution with pH below that (acidic) will make the phenolphthalein hold onto its proton and be colourless. Any pH above that will cause it to lose its proton and become pink.
Explanation:
Heat required : Q = 83500 J = 83.5 kJ
<h3>
Further explanation
</h3>
Given
mass ice = 250 g at 0°C
Required
The heat required
Solution
The heat to change the phase can be formulated :
Q = m.Lf (melting/freezing)
Lf=latent heat of fusion
Input the value :
Q = 250 g x 334 J/g
Q = 83500 J