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CaHeK987 [17]
3 years ago
13

A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 5 tables is $49 . The total cost to r

ent 9 chairs and 7 tables is $77 . What is the cost to rent each chair and each table?
Mathematics
2 answers:
andreev551 [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Fed [463]3 years ago
5 0
Modeling the above problem in matrix form we have,
[3 5;9 7]*[x y]'=[49 77]'
AX=b
X=inv(A)*b
X=[1.7500 8.7500]'
ie x=1.7500 and y=8.7500
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Find two equivalent ratios for 3:4 using multiplication<br><br> A. 6:8<br> B.9:12<br> C. 6:12
Alchen [17]

Answer:

A and B

Step-by-step explanation:

3:4 multiplied by 2 is 6:8

3x2=6 4x2=8

3:4 multiplied by 3 is 9:12

3x3=9 4x3=12

6 0
3 years ago
Read 2 more answers
Identify the interval on which the quadratic function is positive.
Alenkasestr [34]

Answer:

\textsf{1. \quad Solution:  $1 < x < 4$,\quad  Interval notation:  $(1, 4)$}

\textsf{2. \quad Solution:  $-2 < x < 4$,\quad  Interval notation:  $(-2, 4)$}

Step-by-step explanation:

<h3><u>Question 1</u></h3>

The intervals on which a <u>quadratic function</u> is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a negative leading coefficient, the parabola opens downwards.   Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x-1=0 \implies x=1

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is positive is:

  • Solution:  1 < x < 4
  • Interval notation:  (1, 4)

<h3><u>Question 2</u></h3>

The intervals on which a <u>quadratic function</u> is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the <u>quadratic function</u> are the points at which the parabola crosses the x-axis.  

As the given <u>quadratic function</u> has a positive leading coefficient, the parabola opens upwards.   Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given <u>quadratic function</u>, substitute y = 0 and factor:

\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}

Apply the <u>zero-product property</u>:

\implies x+2=0 \implies x=-2

\implies x-4=0 \implies x=4

Therefore, the interval on which the function is negative is:

  • Solution:  -2 < x < 4
  • Interval notation:  (-2, 4)
3 0
1 year ago
and are independent Gaussian (Normal) random Variables. has mean 13.9 and variance 5.2; has mean 6.9 and variance 3.8. . (a) Cal
omeli [17]

This question is incomplete, the complete question is;

X and Y are independent Gaussian (Normal) random Variables. X has mean 13.9 and variance 5.2; Y has mean 6.9 and variance 3.8. . (a) Calculate P( W> 10)

Answer:

P( W> 10) is 0.1587

Step-by-step explanation:

Given that;

X ⇒ N( 13.9, 5.2 )

Y ⇒ N( 6.9, 3.8 )

W = X - Y

Therefore

E(W) = E(X) - E(Y)

= 13.9 - 6.9 = 7

Var(W) = Var(X) + Var(Y) -2COV(X.Y)

[ COV(X,Y) = 0 because they are independent]

Var(W) = 5.2 + 3.8 + 0

= 9

Therefore

W ⇒ N( 7, 9 )

so

P( W > 10 )

= 1 - P( W ≤ 10 )

= 1 - P( W-7 /3   ≤   10-7 /3 )

= 1 - P( Z ≤ 1 )           [ Z = W-7 / 3 ⇒ N(0, 1)  ]

from Standard normal distribution table, P( Z ≤ 1 )  = 0.8413

so

1 - P( Z ≤ 1 )  = 1 - 0.8413 = 0.1587

Therefore P( W> 10) is 0.1587

8 0
3 years ago
A line passes through the points (4,9) and (12,20) what is the slope of the line?
ad-work [718]
Slope form y2-y1 / x2-x1 = m
20 - 9 = 11
12 - 4 = 9

The slope of the line is 11/9
8 0
3 years ago
Read 2 more answers
What is equation created from the sqrt(x+2)+2))^2
Naddika [18.5K]

Answer:

x + 4√(x + 2) + 6

Step-by-step explanation:

All we need to do is expand by using FOIL (First, Outside, Inside, Last):

x + 2 + 2√(x + 2) + 2√(x + 2) + 4

Then we combine like terms to get our final answer:

x + 2 + 4√(x + 2) + 4

x + 4√(x + 2) + 6

8 0
3 years ago
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