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Vika [28.1K]
3 years ago
15

Question In Picture, Thanks.

Mathematics
1 answer:
Ainat [17]3 years ago
5 0
6z to the 4th power - 2z to the 3rd power
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65% of what number is 39
lys-0071 [83]
65% of 39 is 60 the answer is 60
6 0
3 years ago
Read 2 more answers
Given f(x) = 2x + 3 and g(x) = x - 9, what is f(x) + g(x)?
Orlov [11]
Solution:

f(x) = 2x + 3
g(x) = x - 9

f(x) + g(x)
= (2x + 3) + (x - 9)
= 2x + x + 3 - 9
= 3x - 6
6 0
3 years ago
2 + 1/6a = -4 what is a
horsena [70]

Answer:

I found that it was -1, but everything online is telling me -36.

6 0
3 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
U guys are mean and never answer my questions, like i paid for no one to answer my question
Sav [38]

Answer:

Step-by-step explanation:

You have no grounds for making a statement like that.  There are a variety of reasons why you might not get immediate answers.  Be patient.

I will do the second part of this question (finding the first three numbers):

a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50

a(3) = 50

a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16

a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6

The procedure for finding a(5), a(6) and a(7) is exactly the same.

3 0
3 years ago
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