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Vika [28.1K]
4 years ago
15

Question In Picture, Thanks.

Mathematics
1 answer:
Ainat [17]4 years ago
5 0
6z to the 4th power - 2z to the 3rd power
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What is the completely factored form of the expression 16x2 8x 32? 4(4x2 2x 8) 4(12x2 4x 28) 8(2x2 x 4) 8x(8x2 x 24)
Sergio [31]

An expression is defined as a set of numbers, variables, and mathematical operations. The factored form of the expression 16x²+8x+32 is 8(2x²+x+4).

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The completely factored form of the expression can be written as,

16x^2+8x+32\\\\=8(2x^2+x+4)

Thus, the factored form of the expression 16x²+8x+32 is 8(2x²+x+4).

Learn more about Expression:

brainly.com/question/13947055

4 0
2 years ago
Solve for x<br> 3(2х-3) + 4(2-x) = 0
defon

Answer:

x=.5

Step-by-step explanation:

6x-9+8-4x=0

6x-4x=2x

-9+8=-1

2x-1=0

2x=1

x=.5

5 0
3 years ago
Read 2 more answers
What is the solution to the equation + 5= 8?
egoroff_w [7]

Answer:

x=13x=13

Step-by-step explanation:

x−5=8

1

 

Add 55 to both sides.

x=8+5x=8+5

2

 

Simplify  8+58+5  to  1313.

x=13x=13

7 0
3 years ago
Read 2 more answers
Find the compound interest on $12000 for 3 years at 10% per annum compounded annually.​
harkovskaia [24]

Answer: 15,600

Step-by-step explanation: hope it helps

5 0
3 years ago
A quantity P is an exponential function of time I, such that P = 160 when t = 6 and P = 150 when I = 4. Use the given informatio
Klio2033 [76]

Answer:

  • k = 0.032
  • P0 = 131.836

Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

  P(t)=P_0\cdot e^{kt}

We know from the given points that we can write the equation as ...

  P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t

Comparing this to the desired form, we see that ...

  P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693

So, the approximate equation for P is ...

  P(t)=131.836\cdote^{0.032t}

And the parameters of interest are ...

  • k = 0.032
  • P0 = 131.836
4 0
3 years ago
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