Answer:
2<∛13<3 1<∛6<2
Step-by-step explanation:
Lets find the integers a and b ∛13 lies between.
a<∛13<b
a³<13<b³
=> a=2 so 2³=8 and b=3 so 3³=27 8<13<27
Similarly a<∛6<b
a³<6<b³
a=1 and b=2
4. x^10
5. x^3
I hope this helped! Mark me Brainliest! :) -Raven❤️
Answer:
the amswer is c
Step-by-step explanation:
Step-by-step explanation:
(f+g)(x) ➡ f(x) + g(x) ➡ 6x^2 + 2x -7 + 4x - 3 =6x^2 + 6x - 10
(f-g)(x) ➡ f(x) - g(x) ➡ 6x^2 + 2x - 7 -4x + 3 = 6x^2 -2x -4
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
