1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Genrish500 [490]
3 years ago
15

HELP MEH PLS ps the answer is not 2.5

Mathematics
2 answers:
mash [69]3 years ago
8 0
<h3>Answer: Approximately 2.483 hours </h3>

=========================================================

Explanation:

Justin can do the full project by himself in 6 hours. This means his rate is 1/6 of a project per hour. In other words, in one hour, he gets 1/6 of the project done.

Jason can do the full project in 9 hours, so his rate is 1/9 of a project per hour, if he works alone.

Jacob's rate is 1/8 of a project per hour since he can get the job done in 8 hours if he works alone.

-----------

So we have these unit rates

  • Justin's rate = 1/6
  • Jason's rate = 1/9
  • Jacob's rate = 1/8

The units for each rate is projects per hour.

The total rate is

1/6 + 1/9 + 1/8

12/72 + 8/72 + 9/72

(12+8+9)/72

29/27

If the three brothers work together, and no person slows down another, then the rate at which they work together is 29/72 projects per hour. In short, they get 29/72 of the project done in 1 hour.

Let x be the number of hours needed to get the project done if they work together. Multiplying this time value with the rate leads to the amount of the project done. We want the result to be 1 to indicate a full project is complete.

(rate)*(time) = amount done

(rate)*(time) = 1 full project

(29/72)*(x) = 1

x = 1*(72/29)

x = 72/29

x = 2.48275862068966

x = 2.483

It'll take about 2.483 hours to get the job done if they work together. Again this assumes that they don't get in each others way to slow each other down.

Dominik [7]3 years ago
7 0
2.483 if you do the math and what the other comment says you’ll get it right
You might be interested in
Please help
bezimeni [28]

Answer:

26-4s=9s

26-(4s-9s)=0

26+5s=0

5s=-26

ans: s= -26/5

-3r+10=15r-8

-3r-15r=-8-10

-18r=-18

18r=18

ans: r=1

-9(t-2)=4(t-15)

-9t+18=4t-60

-9t-4t=-60-18

-13t=-78

13t=78

ans: t=26

THERE U GO! :D

5 0
2 years ago
Read 2 more answers
How do you write this in standard notation<br><br>6x10 to the power of 3
Olin [163]
The way to write this would be 6000
7 0
3 years ago
Half of the boys in mrs.patricks homeroom 1/4 of them wear glasses how many boys in mrs.patricks homeroom wear glasses
goldfiish [28.3K]

Answer:

ummm be more specific and i can answer it for u!

Step-by-step explanation:

5 0
3 years ago
Find the equation for the horizontal line that goes through point M(a, b).
elena-14-01-66 [18.8K]

Horizontal means zero slope, or a zero coefficient on x.

Answer: y = b



6 0
3 years ago
Read 2 more answers
X+(-13) = -5<br> if anyone can help me out , thank you &lt;3
olga2289 [7]

Answer:

x=8.

Step-by-step explanation:

x+(-13)=-5 makes x =8.

reason:

(-13)+??=-5.

-5+8=-13

therefore x=8

5 0
3 years ago
Other questions:
  • help me if you can...20-22 the midpoint M and one endpoint of GH are given. find the coordinates of the other endpoint.
    12·1 answer
  • A sample of 1200 computer chips revealed that 45% of the chips fail in the first 1000 hours of their use. The company's promotio
    7·1 answer
  • What are the steps to do 4z−(−3z)
    14·2 answers
  • Pick the correct description of the line 2y = 10
    11·2 answers
  • Solve the system of equations below by graphing them with a pencil and
    8·2 answers
  • PLZ HELP?!?! I WANNA CHECK MY ANSWERS ONLY PLS HELP CHECK IF THEY ARE CORRECT?!
    14·1 answer
  • Find the value of x in each case.
    15·1 answer
  • The math club is selling gift wrap for a funraiser. They sold 45 rolls of soild wrapping paper at $4 each and rolls of patterned
    12·1 answer
  • Solve this system of equations:
    13·1 answer
  • Help............................
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!