X + y = 2 —> y = 2 - x
insert to first equation
2-x=x^2-3x-6
x^2 - 3x - 6 - 2 + x = 0
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2
A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2
B: (x - 5i)^2
= (x + - 5i)(x + - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2
C: (x - 5i)(x + 5i)
= (x + - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2
D: (x + 10i)(x - 15i)
= (x + 10i)(x + - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
= - 150i^2 + 5ix + x^2
Hope that helps!!!
Draw something personally offensive to the viewer (nothing inappropriate). Or you could simply add the subjects of your argument into the drawing.
<h2>3</h2>
S<--->T
T<--->S
Same thing
<h2>4</h2>
Both sides a equivalent therefore both triangle areas are also equivalent
The segment to draw is segment UT
Step-by-step explanation:
A line segment is a part of a line that is bounded by two two distinct end points. In this case, segment UT is bounded by endpoints U and T. In the diagram, point R is not a segment but a point of intersection of segments BT and EU.
Learn More
Construction of a line segment: brainly.com/question/9716065
Keywords : proof, statement, reason, segments, reflexive property
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