Arc CD is One-fourth of the circumference of a circle. What is the radian measure of the central angle?

I need help with adding and subtracting fractions

solmaris [256]

Answer is 3/72

multiply the denominator and numerator of 3/8 by 9 (27/72)
multiply the denominator and numerator of 3/9 by 8 (24/72)

this is to get the same denominator of 72

then just subtract
27/72 - 24/72 = 3/72

7 0

3 years ago

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Que How does your tessellation with triangles relate to hexagons and tessellating the plane? Type your response in the space bel

madreJ [45]

For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have

Shape Tessellate?

Octagon No

Hexagon Yes

Pentagon No

Square Yes

Triangle No(unless it is specified that it is an equilateral triangle)

5 0

1 year ago

A pet store was selling 4 lizards for $47.88. If they ended up selling 6 lizards, how much would they have earned?

fgiga [73]

Answer:

Step-by-step explanation:

Step one- Find out how much it costs for one Lizard In this case, for four lizards it costs $47.88. To find the price for one lizard you divide 47.88 by four

$47.88/4Lizards=$11.97 per lizard.

Step two- Now that we have the price for one lizard, your question asks you how much for 6 lizards. We need to find that cost. To do so you multiply $11.97 by 6 for the lizards.

Your answer is $71.82

Hope This Helped :)

4 0

3 years ago

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What is 9 to the of 3

MrRa [10]

Answer:

729

Step-by-step explanation:

8 0

2 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago