The real solutions of f(x) = 0 is; x = -8, 0 and 4
<h3>How to find the roots of a polynomial graph?</h3>
When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.
Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.
From the given graph, the real solutions are at x = -8, 0 and 4
Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4
Read more about Polynomial roots graph at; brainly.com/question/14625910
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72 is the length d of how deep end in feet}
<h3>x²+5x+3+2x²+10x15 =0</h3><h3>x²+2x²+5x+10x+3+15=0</h3><h3>3x²+15x+18=0</h3><h3>3(x²+5x+6) =0 because 3 is common factor</h3><h3>3(x²+3x+2x+6) spill the middle term</h3><h3>3(x(x+3)+2(x+3) take the common factor from term</h3><h3>3(x+2) (x+3)</h3>
<h3>answer is 3(x+2) (x+3)</h3>
please mark this answer as brainlist
