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Dominik [7]
3 years ago
15

Easy 80 points!!!! easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!e

asy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!easy 80 points!!!!
The figures show the dimensions of a tennis court and a basketball court given in terms of the width, x (in feet), of the tennis court.

a. Write an expression for the perimeter of each court.simplify expressions
A. Tennis: ( YOUR WORK)
A. Basketball: (YOUR WORK)


b. If x=36 feet wide. Find length and width of each court.
B. Tennis: (YOUR WORK)
B. Basketball: (YOUR WORK)

Mathematics
2 answers:
Setler [38]3 years ago
6 0

Answer:

A. Tennis: 6x+12

A. Basketball: 7x+36

B. Tennis: Length- 36, Width- 72

B. Basketball: Length- 50, Width: 94

Step-by-step explanation:

A. Tennis

perimeter equation: P= 2L+2W

P=2(x)+2(2x+6) simplify

P= 2x+4x+12

P=6x+12

A. Basketball

P= 2(1/2x+32)+2(3x-14) simplify

P=7x+36

B. Tennis and basketball

just plug in 36 for x for the original lengeth and width equations for each court

svp [43]3 years ago
6 0

Answer:

I think A basketball.

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Answer:

14.8

Step-by-step explanation:

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8+6.8

14.8

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Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)
dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

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Do you need all the math in the world
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Yes!

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Write the equation of a line that goes through point (0,1) and has a slope of 0
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I am joyous to assist you anytime.

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Answer:

<h2>In the attachment</h2>

Step-by-step explanation:

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A slope

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