Answer:
Bill needs to sell 50 pairs of men’s clothes.
Step-by-step explanation:
50y = 2500
Divide by 50 on both sides
2500/50 = 50
<span>(14+x)^2= 25^2 +x^2
14^2 + 28x + x^2 = </span><span>25^2 +x^2
28x = 25^2 - 14^2
28x = 625 - 196
28x = 429
x = 15.32</span>
Answer:
280 ft squared
Step-by-step explanation:
To find the area of the nonshaded portion, we can find the area of the entire floor and then subtract the shaded area.
The total area is that of a rectangle: 30 * 15 = 450 ft squared.
Now, the shaded region is made up of a rectangle and a triangle.
- The rectangle has length 8 and width 10, so its area is 10 * 8 = 80 ft squared.
- The triangle has base 12 and height 15, so using the area of a triangle formula: 
(where b is the base and h is the height) = (12 * 15)/2 = 180/2 = 90 ft squared.
- The total shaded region is: 80 + 90 = 170 ft squared
Subtract 110 from 450: 450 - 170 = 280 ft squared.
Thus, the answer is 280 ft squared.
Hope this helps!
Remember solving inequalities is setting up two smaller inequalities one positive one negative. Also, when you divide or multiply by a negative number to solve for x the inequality changes over.
Based on the calculations, the coordinates of the mid-point of BC are (1, 4).
<h3>How to determine coordinates of the mid-point of BC?</h3>
First of all, we would determine the initial y-coordinate by substituting the value of x into the equation of line that is given:
At the origin x₁ = 0, we have:
y = 2x + 1
y₁ = 2(0) + 1
y₁ = 2 + 1
y₁ = 3.
When x₂ = 2, we have:
y = 2x + 1
y₂ = 2(2) + 1
y₂ = 4 + 1
y₂ = 5.
In order to determine the midpoint of a line segment with two (2) coordinates or endpoints, we would add each point together and divide by two (2).
Midpoint on x-coordinate is given by:
Midpoint = (x₁ + x₂)/2
Midpoint = (0 + 2)/2
Midpoint = 2/2
Midpoint = 1.
Midpoint on y-coordinate is given by:
Midpoint = (y₁ + y₂)/2
Midpoint = (3 + 5)/2
Midpoint = 8/2
Midpoint = 4.
Therefore, the coordinates of the mid-point of BC are (1, 4).
Read more on midpoint here: brainly.com/question/4078053
#SPJ1
