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Dmitrij [34]
3 years ago
7

What is f(5) for the function f(x)=2x+7

Mathematics
2 answers:
denis-greek [22]3 years ago
8 0

Answer:

Solution:

f(5)=2×5+7

=10+7

=17

vitfil [10]3 years ago
4 0

Answer:

f(5)=17

Step-by-step explanation:

f(5)=2(5)+7\\f(5)=10+7\\f(5)=17

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If I had know ill,I would gone to visit you sentence using appropriate conditional classe​
quester [9]

Answer:

was this supposed to be funny lol

Step-by-step explanation:

5 0
3 years ago
⎧
MrRissso [65]

Answer:

f(n)=-5-3n

Step-by-step explanation:

Given the recursive formula of a sequence

f(1)=−8

f(n)=f(n−1)−3

We are to determine an explicit formula for the sequence.

f(2)=f(2-1)-3

=f(1)-3

=-8-3

f(2)=-11

f(3)=f(3-1)-3

=f(2)-3

=-11-3

f(3)=-14

We write the first few terms of the sequence.

-8, -11, -14, ...

This is an arithmetic sequence where the:

First term, a= -8

Common difference, d=-11-(-8)=-11+8

d=-3

The nth term of an arithmetic sequence is determined using the formula:

T(n)=a+(n-1)d

Substituting the derived values, we have:

T(n)=-8-3(n-1)

=-8-3n+3

T(n)=-5-3n

Therefore, the explicit formula for f(n) can be written as:

f(n)=-5-3n

7 0
3 years ago
What is 36.993 to the nearest thousandth
finlep [7]

The next larger thousandth is 36.994 .
The next smaller thousandth is  36.992 .
Neither of those is any nearer to  36.993
than  36.993  already is.

The last '3' at the end of 36.993 is in the thousandths' place.
There is no more piece of another thousandth after it.
So  36.993 is already on a complete thousandth, and
there's no rounding required.

7 0
3 years ago
If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

6 0
3 years ago
Another one the last one ASAP
kodGreya [7K]

Answer:

13m²

Step-by-step explanation:

Area=6.5*4÷2=13

6 0
2 years ago
Read 2 more answers
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