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3 years ago

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Robert spent half of his savings on a new phone. He earns some money back by babysitting the neighbors for $45. What was his sav

ings if he ended with $107? Can you help with this question and put it in step-by-step?

1 answer:

g100num [7]3 years ago

8 0

The answer is 169 I’m pretty sure

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The number of quarters required to play an arcade game varies directly with the number of levels played. The game requires 9 qua

dexar [7]

Answer:

45 quarters

Step-by-step explanation:

1. Think of this as the ration equation 9/3=x/15 where x is the number of quarters to play 15 levels

2. To solve the ratio, you need to cross multiply, and then divide

3. Multiply 9 times 15 (135)

4. Divide that number by 3 (45), and that's your answer!

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3 years ago

As an estimation we are told £3 is €4.<br> Convert £33 to euros.

Triss [41]

Answer:

44 euros

Step-by-step explanation:

if the ratio between an english pound and a euro is 3 to 4 respectivley, the ratios will hold true for any number. Since 33/3 = 11, we can stratigically multiply by 1,

3/4 = (3/4)(11/11)

so the ratios would be the same, multiplying, you would get 33/44, which means 33 pounds for 44 euros

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3 years ago

lara [203]

Answer: Carlton's cabs is the cheaper option if she wants to travel 15 miles.

Step-by-step explanation:

A linear relationship can be written as:

c = a*n + b

where a is the slope (in this case, the rate per mile), n is the number of miles driven by the taxi, and b is the y-axis (in this case, the initial cost) intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Then for each table we only need to take two points and construct the linear equation:

Treveon's Taxis:

We can use the two points (1, $5.25) and (3, $9.75)

Then the rate per mile, or the slope, will be:

a = ($9.75 - $5.25)/(3 - 1) = $2.25

This means that each mile costs $2.25

Then the equation will be written as:

c = $2.25*n + b

To find the value of b, we can just replace one of the points in the equation. For example, I will se the point (1, $5.25) this means that we need to replace n by 1, and c by $5.25

Then:

$5.25 = $2.25*1 + b

$5.25 - $2.25 = b

$3 = b

Then the initial cost here is $3.

And the equation will be:

c = $2.25*n + $3.

Carlton's Cabs:

Same approach as before, here I will use the points (1, $7.00) and (3, $10.50)

Then the rate per mile will be:

a = ($10.50 - $7.00)/(3 - 1) = $1.75

The rate per mile is $1.75 (is cheaper than in the previous case)

Then at the moment, the equation is:

c = $1.75*n + b

To find the initial cost, we do the same as before, here i will use the point (1, $7.00)

$7.00 = $1.75*1 + b

$7.00 - $1.75 = b

$5.25 = b

The initial cost here is $5.25

And the equation will be:

c = $1.75*n + $5.25

Now, which one is cheaper for 15 miles?

We only need to replace n by 15 in both equations, and see in which one the cost is lower:

Treveon's Taxis:

c(15) = $2.25*15 + $3 = $36.75

Carlton's Cabs:

c(15) = $1.75*15 + $5.25 = $31.5

Then Carlton's Cabs is a better option if you want to travel 15 miles.

6 0

3 years ago

Find the four rational numbers and irrational numbers between 2/5 and 5/6

Savatey [412]

The four?

Of course there are an infinite number of rationals between any two different real numbers, as well as an even bigger infinite number of irrationals.

The average will be between the numbers:

$\frac 1 2 (\frac 2 5 + \frac 5 6) = \dfrac{37}{60}$

That's a lot of work to get a number in between. We can just see

$\frac 1 2$
is between the two numbers.

The mediant, or freshman addition, will always be in between:

$\dfrac{2 + 5}{5 + 6} = \dfrac{7}{11}$

2/5=.4 and 5/6 is about .83, so

$.6 = \frac{6}{10}$

is in between as is .7, .41, .530940394 and as many rationals as we care to generate.

To get irrationals we could just add a teeny irrational to the ones we just generated, like $\frac{6}{10} + \frac{\pi}{100}$

We could just change that denominator a bit and get as many as we like.

But let's get some square roots. The geometric mean will be between

$\sqrt{ \dfrac 2 5 \cdot \dfrac 5 6 } = \dfrac{1}{\sqrt{3}}
$

That's the tangent from one of trig's biggest cliches, but I digress. It's in between.

While we're on trig cliches,

$\dfrac{1}{\sqrt{2}}$

is in between as well.

Keeping with the trig theme, also in between are

$\dfrac{\pi} 6$

and

$\dfrac{\pi}{4}$

the angles associated with the some of the above trig function values.

We could obviously go on as long as we cared to.

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4 years ago

Does anyone ply Pokémon go ?

hammer [34]

Answer: I used to, but it got boring

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers