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Serggg [28]
3 years ago
8

Solve the equation 2x+1=x-3​

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

How to solve your problem

Topics: Algebra, Quadratic Equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

Solve

1

Subtract

1

1

1

from both sides of the equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

2

+

1

−

1

=

−

3

−

1

2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}

2x+1−1=x−3−1

2

Simplify

Subtract the numbers

Subtract the numbers

2

=

−

4

2x=x-4

2x=x−4

3

Subtract

x

x

from both sides of the equation

2

=

−

4

2x=x-4

2x=x−4

2

−

=

−

4

−

2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}

2x−x=x−4−x

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

−

4

x=-4

x=−4

Solution

=

−

4

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                - - - - - - - - - - - - - - - - - - - - - - - - -- - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Given question:-}}}}

             ❖ A number y increased by 5 is at least -21.

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}

          ❖ First, if you come across the word "increased" it means we

    "increase" a number, or add something to that number, like

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Now, we are also given that this expression is at least -21, which means it can't be -21; it can be -21 or it can be greater than -21.

So we have

\longmapsto\sf{y+5\geq -21}}

<em>Solving for y</em>

<em></em>

  •   Subtract 5 on both sides:-

\longmapsto\sf{y\geq -21-5}

\longmapsto\sf{y\geq -26}

So the values of y greater than or equal to -26 will make this inequality true.

<h3>Good luck with your studies.</h3>

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