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Serggg [28]
3 years ago
8

Solve the equation 2x+1=x-3​

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

How to solve your problem

Topics: Algebra, Quadratic Equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

Solve

1

Subtract

1

1

1

from both sides of the equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

2

+

1

−

1

=

−

3

−

1

2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}

2x+1−1=x−3−1

2

Simplify

Subtract the numbers

Subtract the numbers

2

=

−

4

2x=x-4

2x=x−4

3

Subtract

x

x

from both sides of the equation

2

=

−

4

2x=x-4

2x=x−4

2

−

=

−

4

−

2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}

2x−x=x−4−x

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

−

4

x=-4

x=−4

Solution

=

−

4

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Consider the system of equations.
jok3333 [9.3K]

Given:

The system of equations:

x-3y=9

\dfrac{1}{5}x-2y=-1

To find:

The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.

Solution:

We have,

x-3y=9                        ...(i)

\dfrac{1}{5}x-2y=-1       ...(ii)

The coefficient of x in (i) and (ii) are 1 and \dfrac{1}{5} respectively.

To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.

It means, we have to convert \dfrac{1}{5} into -1. It is possible if we multiply the equation (ii) by -5.

On multiplying equation (ii) by -5, we get

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On adding (i) and (iii), we get

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Here, x is eliminated.

Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.

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2 years ago
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