Standard deviation of the data. 221,228,218,319,224

Describe when to use a series and when to use an equation.

anyanavicka [17]

Answer:

An equation is used when we have paired sets of data to describe how the values in one pair change when we alter the values in the other set.

On the other hand, a series gives a general formula of determining the value of the nth observation when the values have been arranged in increasing order

Step-by-step explanation:

An equation such as; y = 3x+5 models the relation between the response variable y and the predictor variable x. It tells us how y changes when x is altered by a certain magnitude. The value 3 is described as the slope while 5 is the y-intercept.

On the other hand, a series such as; score = 2 + 3n provides a general formula that can be used to determine the score of the nth individual in a sample or population.

5 0

3 years ago

The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between (height) and (arm span) is shown

sergeinik [125]

Answer: Mike's arm span is 7.165 cm longer than the George's one.

Step-by-step explanation:

We have that the association between height and arm span is modeled by the equation

y = 4.5 + 0.977*x

where y is height and x is arm span.

Mike is 172 cm tall, so his arm span is:

172cm = 4.5 + 0.977*x

x = (172 - 4.5)/0.977 = 171.443 cm

and George is 165 cm tall, so his arm span is:

x = (165 - 4.5)/0.977 = 164.278 cm

Then the difference between their arm span is:

171.443cm - 164.278cm = 7.165 cm

So Mike's arm span is 7.165 cm longer than the George's one.

6 0

3 years ago

Given that Triangle ABC ~ DEF, solve for X.

Vadim26 [7]

Answer:

x = 7

Step-by-step explanation:

if ABC ~ DEF than AB ~ ED, AC ~ DF, and CB ~ FE

The ratio of AB to ED is given as 5/30 = 1/6

For AC ~ ED the ratio would be same x/42 = 1/6 cross multiply it

6x = 42

x = 7

6 0

3 years ago

A student solved the following problem and made an error: Triangles ABC and DEF. Angles A and F are congruent and measure 135 de

dmitriy555 [2]

We have that
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)

triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)

using a graph tool
see the attached figure

therefore

Line 1 Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct

Line 2 ∠A ≅ ∠F------> is correct

Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83

find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct

Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47

find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct

Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct

therefore

the answer is
the student make the first mistake in line 5