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3 years ago

HELP ME ?

Mathematics

1 answer:

julsineya [31]3 years ago

7 0

1. $\sqrt{11}$ is less than 3.5

2. $\sqrt{5}$ is more than 2.1

3. -5.3 is more than -5 $\frac{3}{5}$

4. $\frac{8}{10}$ is less than 0.8 repeating

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Geometry

SSSSS [86.1K]

Sorry man, don’t know it, hopefully you get someone who knows

7 0

3 years ago

Answer....... (-1)^3×(-1)^2

8090 [49]

Hello there!

(-1)^3 * (-1)^2

Use the distributive property

= (-1)(-1)(-1)* (-1)(-1)

= (-1)^5

= -1

I hope this helps!

3 0

3 years ago

Pleasssssssss help 5<br> points

love history [14]

What is the situation from the problem

7 0

3 years ago

Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.

Yakvenalex [24]

The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as

v+ = 2.29 1mile/hour

<h3>What is the rate Evelyn and Meredith were paddling?</h3>

Generally, the equation for the up and downstream motion is mathematically given as

vup=v-2

vdown=v+2

Therefore, Statement interpretation

2/3=40*1/60

3+2/3hr=11/3

Where, tup+tdown=11/3

tup+tdown=11/3

1/Vup+1/vdown=11/3

Considering the LCD equation

3(v-2)(V+2)

Hence

$\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}\\\\3(v+2)+3(v-2)=11(v+2)(v-2)$

11v^2-6v-44=0

$v=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Resolving using the equation we have

v+ = 2.29 1mile/hour

v- = -1.745 mile hour

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2 years ago

Explain why it is important to solve for the variable first in order to find the measure any angle mentioned in the problem . Ye

valkas [14]

In the field of astronomy, the ability to measure angles accurately and precisely enables us to calculate the position and relative movement of the stars and galaxies in relation to each other, to determine how far distant they are from us, and even to estimate their relative size.

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