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3 years ago

Help Please 8 points and Brainliest if correct!!!

Mathematics

2 answers:

mariarad [96]3 years ago

8 0

Answer:

The answer is 22

The sum of two numbers is 48:

x + y = 48 ⇒ x = 48 - y

One third of one number is 5 greater than one sixth of another number:

1/3x =5 + 1/6 y

1/3(48 - y) = 5 + 1/6y

1/3 * 48 - 1/3 * y = 5 + 1/6 y

16 - 1/3y = 5 + 1/6y

16 - 5 = 1/6y + 1/3y

11 = 1/6y + 2/6y

11 = 3/6y

y = 11 * 6 / 3

y = 22

x = 48 - y

x = 48 - 22

x = 26

The smallest number is 22.

Step-by-step explanation:

Troyanec [42]3 years ago

6 0

Answer:

-3/4^10

Step-by-step explanation:

you multiply powers 5 and 2

-3/4 ^10

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Fiesta28 [93]

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2.3 x 10⁴

Step-by-step explanation:

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3 years ago

!!!PLEASE HELP ASAP!!! <br> I WILL GIVE MORR POINTS IF NEEDED AND MARK BRAINLIEST

Firlakuza [10]

The first one shows 1 cm and 7 mm, we need to convert 7 mm to cm
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3 years ago

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

maria [59]

Answer:

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

Step-by-step explanation:

We know that the velocity function is given by

$v(t)=\frac{105t}{6t+17}$

Acceleration is the rate of change of velocity so we take the derivative of the velocity function with respect to time.

$a(t)=\frac{dv}{dt}=\frac{d}{dt} (\frac{105t}{6t+17})$

$\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\105\frac{d}{dt}\left(\frac{t}{6t+17}\right)\\\\\mathrm{Apply\:the\:Quotient\:Rule}:\quad \frac{d}{{dx}}\left( {\frac{{f\left( x \right)}}{{g\left( x \right)}}} \right) = \frac{{\frac{d}{{dx}}f\left( x \right)g\left( x \right) - f\left( x \right)\frac{d}{{dx}}g\left( x \right)}}{{g^2 \left( x \right)}}$

$105\cdot \frac{\frac{d}{dt}\left(t\right)\left(6t+17\right)-\frac{d}{dt}\left(6t+17\right)t}{\left(6t+17\right)^2}\\\\105\cdot \frac{1\cdot \left(6t+17\right)-6t}{\left(6t+17\right)^2}\\\\a(t)=\frac{1785}{\left(6t+17\right)^2}$

a. At t = 5 s

$a(5)=\frac{1785}{\left(6(5)+17\right)^2}=\frac{1785}{2209}\approx0.808 \frac{ft}{s^2}$

b. At t = 10 s

$a(10)=\frac{1785}{\left(6(10)+17\right)^2}=\frac{255}{847}\approx0.301 \frac{ft}{s^2}$

c. At t = 20 s

$a(20)=\frac{1785}{\left(6(20)+17\right)^2}=\frac{1785}{18769}\approx0.095 \frac{ft}{s^2}$

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3 years ago