Which option in a Task element within Outlook indicates that the task is scheduled and will be completed on a later

Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria

butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

if side1 == side2 == side3:

print("Equilateral Triangle")

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

else:

print("Scalene Triangle")

else:

print("Invalid Triangle")

else:

print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

if side1 == side2 == side3:

print("Equilateral Triangle")

Check if the triangle is isosceles

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

Otherwise, it is scalene

else:

print("Scalene Triangle")

Print invalid, if the sides do not make a valid triangle

else:

print("Invalid Triangle")

Print invalid, if the any of the sides are negative

else:

print("Invalid Triangle")

4 0

2 years ago

A digital computer has a memory unit with 16 bits per word. The instruction set consists of 72 different operations. All instruc

OLga [1]

Answer:

a. 7 bits b. 9 bits c. 1 kB d. 2¹⁶ - 1

Explanation:

a. How many bits are needed for the opcode?

Since there are 72 different operations, we require the number of bits that would contain 72 different operations. So, 2ⁿ ≥ 72

72 = 64 + 8 = 2⁶ + 8

Since n must be an integer value, the closest value of n that would contain 72 different operations is n = 7. So, 2⁷ = 128

So, we require 7 bits for the opcode.

b. How many bits are left for the address part of the instruction?

bits left = bits per word - opcode bit = 16 - 7 = 9 bits

c. What is the maximum allowable size for memory?

Since there are going to be 2⁹ bits to addresses each word and 16 bits for each word, the maximum allowable size for memory is thus 2⁹ × 16 = 512 × 16 = 8192 bits.

We convert this to bytes

8192 bits × 1 byte/8 bits = 1024 bytes = 1 kB

d. What is the largest unsigned binary number that can be accommodated in one word of memory?

Since the number go from 0 to 2¹⁶, the largest unsigned binary number that can be accommodated in one word of memory is thus

2¹⁶ - 1

6 0

3 years ago

What is the most useful advantage of using the Slide Sorter view to rearrange slides instead of using the slide thumbnails in No

Eddi Din [679]

b. In Slide Sorter view, the user can zoom in to read text on slides more easily or zoom out to see more of the presentation’s slides at once.
Moreover, in Normal View, the number of slides that you can see together at once is quite less, so it is more advantageous to use the Slide Sorter View to sort your slides

5 0

3 years ago

Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompt

Makovka662 [10]

Answer:

C++

#include <iostream>

#include <cmath>

using namespace std;

///////////////////////////////////////////////////////////////////////

int noOfGallons(int wallArea) {

int gallon = 350;

int gallon_price = 32.0;

float total_price = 0.0;

///////////////////////////////////////////

float noOfGallons = (float)wallArea/(float)gallon;

printf("No of gallons needed %.2f", noOfGallons);

cout<<endl;

//////////////////////////////////////////

total_price = noOfGallons*gallon_price;

return round(total_price);

}

int wallArea(int length, int width, int height) {

int wall_area = length*width;

int total_price = noOfGallons(wall_area);

}

///////////////////////////////////////////////////////////////////////

int main() {

int length, width, height;

///////////////////////////////////////////

cout<<"Enter length: ";

cin>>length;

cout<<"Enter width: ";

cin>>width;

cout<<"Enter height: ";

cin>>height;

cout<<endl;

///////////////////////////////////////////

int total_price = wallArea(length, width, height);

cout<<"Total price: $"<<total_price;

///////////////////////////////////////////

return 0;

}

5 0

2 years ago

Online education students need to be taught

weeeeeb [17]

Online education is a teaching practice delivered through the internet. The students learning from online platforms must be taught to be ethical.

<h3>What is the importance of ethics and integrity?</h3>

In the online education system, the students should learn to be ethical and integral as it enables the students and their teachers to be creative, free to create ideas, and acknowledge others' work.

Ethics teaches the students to develop their personalities and behavior. Students' integrity allows them to be honest, responsible, and fair towards their work and instructor.

Therefore, option A. online learning students must be taught to be ethical.

Learn more about online learning here:

brainly.com/question/14708323

#SPJ1

7 0

2 years ago