3 years ago

Please help in maths

Mathematics

1 answer:

34kurt3 years ago

8 0

Answer:

$(3d^{4})^{2} = 9d^{8}$

option B is correct

Step-by-step explanation:

You might be interested in

thisss guyyy iss looooking fine . but why so serioussss hahahaha. when guysss be looking at you like this. does it make you blus

Elza [17]

Answer:

no- it doesnt make me blush- and uh- i look at them and then away- and then start to draw or read-0-0

Step-by-step explanation:

5 0

3 years ago

Giving brainliest for correct answer!

Mamont248 [21]

Answer:

10 7

20 14

30 21

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP ME ASAP!!! ITS ALMOST DUE!! ILL MARK BRAINLIEST!!

Gelneren [198K]

Answer:

4.2

Step-by-step explanation:

closest to what I counted 3

8 0

3 years ago

4 1/2 + 1 + 2 + 1 1/4 + 1/2 + 2/4 how did you get the answer

Anestetic [448]

Your answer is 9 3/4.

6 0

3 years ago

Read 2 more answers

Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb

Umnica [9.8K]

Answer:

It would roll in this direction.

$\nu = (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})$

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.

Since

$z = ax^2 + by^2$

For this case, the gradient of your function would be

$\nabla z = (2ax , 2by)$

And -1 times the gradient of your function would be

$-\nabla z = (-2ax , -2by)\\$

Then, at

$(1,1,a+b),\\x = 1 \\y = 1$

So it would go towards

$v = (-2a,-2b)$

The magnitud of that vector is

$|v| = 2\sqrt{a^2+b^2}$

and to conclude it would roll in this direction.

$\nu = (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})$

6 0

3 years ago