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Ivan
2 years ago
13

Question 11 plz, really need help

Mathematics
2 answers:
madam [21]2 years ago
7 0

Answer:

ummm hold on im trying to figure it out sorry might take long  

fgiga [73]2 years ago
7 0
I’m trying to see ,
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For breakfast, Paula bought a bagel for $1.05 and a glass of orange juice for $1.95. At lunch, Paula spent $5.00 on a sandwich a
Dennis_Churaev [7]

Answer:

3.20$

Step-by-step explanation:

3 0
3 years ago
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Raul tossed a coin and spin a spinner with three equal sections. Based upon the results, what is the probability of tossing a ta
Shkiper50 [21]
H is the answer for the question
5 0
3 years ago
A) There are 100 students who play at least one of volleyball, soccer and hockey, of these 50 play au three games, 84 play socce
Scilla [17]

Answer:

<h2>i) 3</h2><h2>ii) 5</h2>

Step-by-step explanation:

Let H be the set of students who play Hokey

     V be the set of students who play Volleyball

     S be the set of students who play Soccer

======================================

card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]

                                 = 73 - [50 + (58-50) + (62-50)]

                                 = 73 - [50 + 8 + 12]

                                 = 73 - 70

                                 = 3

………………………………………………

Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]

                              = 100 - 95

                              = 5

…………………

<u><em>Note</em></u> :

A Venn diagram might be helpful in such case.

5 0
2 years ago
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
3 years ago
Compare the volumes of Prism A and Prism B.
Brut [27]

Answer:

111222333

Step-by-step explanation:

...---...

7 0
2 years ago
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